2006-07-19 09:46:53 · 10 answers · asked by fishermanswife 4 in Food & Drink ➔ Cooking & Recipes
Oh dear god yes!
2006-07-19 09:49:35 · answer #1 · answered by Rich B 7 · 1⤊ 1⤋
yes, you should cook the chicken thoroughly... meats dont typically cook all the way when in sauce (with the except they have been marinated overnight or for a few hours, then browned) but if it is an actual sauce, you need to cook the chicken til it's done before putting it into the sauce...
2006-07-19 16:51:28 · answer #2 · answered by Fatty McButterpants 5 · 0⤊ 0⤋
Yes always brown chicken before simmering it it gives a better appearance and it keeps the skin from getting rubbery
2006-07-19 16:49:58 · answer #3 · answered by Joshua S 1 · 0⤊ 0⤋
Yes...I would definitely cook the chicken first before throwing it into the sauce. You probably don't have to brown the chicken, just fry until it turns opaque ... not necessary to "brown" it.
2006-07-19 16:51:42 · answer #4 · answered by Dee 5 · 0⤊ 0⤋
Yes brown the chicken first other wise the juices from it may make your sauce look yukky, or too watery
2006-07-19 16:53:03 · answer #5 · answered by Curious39 6 · 0⤊ 0⤋
Totally opinated question. Personally, I always brown my chicken. It adds that gret flavor. My wife on the other hand does not. It really is personal preference, but I would do it.
BP
2006-07-19 16:50:30 · answer #6 · answered by billyandgaby 7 · 0⤊ 0⤋
yes in deedy browning it first bring out the colour it carmelizes & it gives you better flavoring & it should be cooked up some so it speeds up your dinner faster so your taste buds dont have to wait so long for them to taste
2006-07-19 16:53:44 · answer #7 · answered by chefgoudah 3 · 0⤊ 0⤋
Definately - it will seal in the natural juices and your chicken will not get dried out.
2006-07-19 16:50:26 · answer #8 · answered by M 3 · 0⤊ 0⤋
yes . . always brown chicken first, it intensifies the flavor
2006-07-19 16:58:21 · answer #9 · answered by Joy L 4 · 0⤊ 0⤋
I would, it makes for better flavor.
2006-07-19 16:49:38 · answer #10 · answered by ptnopt 3 · 0⤊ 0⤋