2006-07-15 17:18:57 · 8 answers · asked by mani 1 in Science & Mathematics ➔ Engineering
It depends upon how hot the water is to start with and how quickly you wish to freeze it.
If you don't care how fast you freeze it then you are looking for energy not power.
Power is energy per time. For example: 1 kW = 1000 watts = 1000 J/s. Joules are the metric units for energy.
2006-07-15 17:26:25 · answer #1 · answered by Engineer 6 · 1⤊ 0⤋
If you want power you also have to state how fast the freezing should be. The total energy removed from the water will be cp*m*deltaT, where cp is the specific heat of water and m is the mass. That energy divided by the time will be the average power.
2006-07-16 04:48:17 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
you need start temperature and end temperature - you'll have the delta T; where T equals temp.
You will need the amount of energy it takes to change one cubic meter of water one degree celsius. (if they give it in joules per cubic centimeter then find out how many cubic cm's are in a cubic m and multiply the amount of energy by the number you get)
after you have found the one degree amount of energy, multiply it by your delta T.
after you've done that, convert your answer into KW.
2006-07-16 00:25:01 · answer #3 · answered by tami 4 · 0⤊ 0⤋
420
2006-07-16 00:21:40 · answer #4 · answered by C J 4 · 0⤊ 0⤋
Depends on the initial temperature of the water.
2006-07-16 00:20:37 · answer #5 · answered by vin 3 · 0⤊ 0⤋
Depends on the method used.
2006-07-16 00:26:52 · answer #6 · answered by xtowgrunt 6 · 0⤊ 0⤋
all depends on the power requirements of your freezer. I would imagine quite a few.
2006-07-16 00:21:58 · answer #7 · answered by nosedeepinpink 1 · 0⤊ 0⤋
You don't state the temp. of the water.
Sea Level ??
Salt ??
Salinity ??
Igneous ??
Metamorphic ??
2006-07-16 00:20:54 · answer #8 · answered by Anonymous · 0⤊ 0⤋