b+1 and b+2 are consecutive numbers so they are prime each other.(there are no common divider except 1. like 8 and 9). the least common multiple of the prime each other numbers is multiplication of the numbers. than l.c.m (b+1) and (b+2) is (b+1)*(b+2)
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2006-07-15 09:13:05
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answer #1
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answered by jacob ecco 1
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The least common mulitple of two numbers is the smallest number (not zero) that is a multiple of both.
Lets take 3 and 4
The multiples of 3 are:
0, 3, 6, 9, 12, ...(3x0=0, 3x1=3, 3x2=6, 3x3=9, 3x4=12....)
The multiples of 4 are:
0, 4, 8, 12, 16,...(4x0=0, 4x1=4, 4x2=8, 4x3=12, 4x4=16....)
Now the mulitiples that both 3 and 4 share that comes first and they both have in common is 12. 12 is the least common mulitple of 3 and 4.
2006-07-15 15:45:47
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answer #2
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answered by livingall_4_god 2
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The data provided is insufficient to help you with an answer. Try framing your question properly.
2006-07-15 14:51:40
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answer #3
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answered by zuluind04 2
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jacob_echo has given a great solution ....jes wanted to say nice thinking......i think ur right.....but the first part isint very convincing......i mean about the prime nos......but come to think of it ....yes its true...good job mate
2006-07-15 20:33:54
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answer #4
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answered by Retrick 2
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