2006-07-13 05:27:47 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
The volume is
50* 0.5(3+8)*72 = 19800 cuft
That comes to 148 114.285 US gallon
2006-07-13 05:34:25 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
Assuming the floor of the pool slopes straight down from 3' to 8' without any flat areas (or that the flat area at the shallow end is the same size as the flat area at the deep end), the average depth of the pool is 5.5'.
So:
50*72*5.5 = 19800 cubic feet
19800 / 0.1336805 (the volume of one gallon in cubic feet) = 148114 gallons.
If the pool has different size flat areas at the ends, it's more complex. You can divide the pool into three imaginary sections - deep end, shallow end, and center section - to get the volume. We'll call the length of the shallow end S and the length of the deep end D. The formula would then be: (S*3 + D*8 + (72-(S+D))*5.5)*50 to get the total volume in cubic feet, or ((S*3 + D*8 + (72-(S+D))*5.5)*50) / 0.1336805 for the volume in gallons. If the slope of the center section is not constant, this will not be absolutely accurate, but it will get you close.
2006-07-13 12:35:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
think of the bottom of the pool like a triangle...take the difference in depths to form the height of the triangle (8foot-3foot=5foot). so to get the volume of a triangular prism (i think that's what it's called) multiply 5*50*72=18000. Next deal w/ the upper portion that's like a box by multiplying 50*72*3=10800. Finally add the two, 18000+10800= 28800. So your pool holds 28800 cubic feet of water. I'm not sure how to convert that into gallons though because I use the metric system. I'll leave that for someone else to figure out.
2006-07-13 12:35:08 · answer #3 · answered by Caroline C 1 · 0⤊ 0⤋
volume=lbh
and here the height/depthis the average depth,which is 11/2
volume=72*50*11/2=19800 cft
US liquid gallon is 231 in³=231/(12*12) cft
vol of water=19800*12*12/231=12342.9gallons
2006-07-13 15:16:26 · answer #4 · answered by raj 7 · 0⤊ 0⤋
The only way to know for sure, would to know the slope from wich is goes 3 feet deep to 8 feet deep.
2006-07-13 12:32:18 · answer #5 · answered by s2point2k 3 · 0⤊ 0⤋
its not possible for us to tell, unless the pool has a constant slope from 3' to 8'. most likely it has a changing slope, in which case you would have to use calculus to solve it, or just fill up the pool to see.
2006-07-13 12:31:16 · answer #6 · answered by Alex F 3 · 0⤊ 0⤋
About 50 zillion man!!
2006-07-13 12:31:30 · answer #7 · answered by Jimmy Pete 5 · 0⤊ 0⤋
what they said
2006-07-13 12:45:22 · answer #8 · answered by Anonymous · 0⤊ 0⤋
It's empty.
2006-07-13 12:30:31 · answer #9 · answered by Ogytor 2 · 0⤊ 0⤋