2006-07-12 20:09:56 · 5 answers · asked by anyemabruce 1 in Education & Reference ➔ Home Schooling
devilishblueeyes is absolutely correct and his logic is impeccable.
However, mathmatically you can use differential calculus to show this. In fact it's exactly what it's for.
You have a function y=x-x^2.
You want it's maximum value. So take the first derivative and set it equal to zero. That will be that maximum (in this case).
dy/dx=0=dx/dx- d(x^2)/dx
0= 1-2x
2x=1
x=1/2
2006-07-13 01:59:57 · answer #1 · answered by Iridium190 5 · 0⤊ 0⤋
1
2006-07-12 20:14:10 · answer #2 · answered by MJA 2 · 0⤊ 0⤋
That answer would have to be 0.5.
0.5 x 0.5 = 0.25 It exceeds it's square by 0.25.
The reason being is that it is in the middle between 0 and 1. As you get closer to 0 or closer to 1 the amount that it exceeds its square decreases towards 0. Once the value of the number decreases below 0 or increases above 1, the difference of the number in relation to its square becomes negative.
2006-07-12 23:53:22 · answer #3 · answered by devilishblueyes 7 · 0⤊ 0⤋
Hmmmm. An integer cannot excede it's square. If it is a negative #, the square will be larger.
If it's a positive number, same deal. Zero and one will be equal when squared. I don't think there is one in regards to integers.
2006-07-12 20:14:23 · answer #4 · answered by csucdartgirl 7 · 0⤊ 0⤋
That would be a Fraction, althought I'm not sure what the specific Fraction would be. Good Calculus question.
2006-07-12 20:16:27 · answer #5 · answered by Anonymous · 0⤊ 0⤋