An explorer was searching a cave when he came across a set of numbers.
He saw 1.
Then he saw 11.
Next, he saw 21
then, 1,211
after that, 111,221
what number did he see after that?
2006-07-11 11:48:42 · 10 answers · asked by sad but cute 2 in Science & Mathematics ➔ Engineering
and tell me how you solved it
2006-07-11 11:57:37 · update #1
He saw the French Grand Slam at Denny's....
That was EASY!!
Thanks.
2006-07-11 11:52:21 · answer #1 · answered by Gravy Czar 4 · 0⤊ 0⤋
1
2006-07-11 18:50:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2
2006-07-11 18:51:15 · answer #3 · answered by Ray T 1 · 0⤊ 0⤋
1,111,112,221
If you look at the totals of the numbers, you get 1, 2, 3, 5, 8 so the next one has to be a sum of 13 because 1+2=3, 2+3=5 and 5+8=13.
Looking at the number of digits in the problem, they add up also, 1, 2, 2, 4, 6. So the next number has to be 4+6 digits long giving you a 10 digit number.
2006-07-12 12:07:23 · answer #4 · answered by Patrick H 2 · 0⤊ 0⤋
312211 - you state the previous numbers. i.e. 1,211= one one, one two, two one or 111221
2006-07-11 18:52:02 · answer #5 · answered by setsunaandkurai 2 · 0⤊ 0⤋
none.
he ran away screaming !
2006-07-11 18:51:37 · answer #6 · answered by rottentothecore 5 · 0⤊ 0⤋
312211 then 13112221 then 1113213211 etc...
2006-07-11 19:06:22 · answer #7 · answered by Anonymous · 0⤊ 0⤋
11112221
2006-07-11 18:52:41 · answer #8 · answered by sparkydog_1372 6 · 0⤊ 0⤋
1,112,211
2006-07-11 18:54:13 · answer #9 · answered by dreco81 1 · 0⤊ 0⤋
11,112,221
2006-07-11 18:53:57 · answer #10 · answered by Anonymous · 0⤊ 0⤋