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2006-07-08 22:02:37 · 3 answers · asked by dinotot0214 1 in Environment

3 answers

enought to make one cool bomb!... that would take care of half of the problems with north korea....

2006-07-08 22:07:58 · answer #1 · answered by steveangela1 5 · 0 0

Depends on what you mean by hydrogen. If by simple conversion of hydrogen atoms to hydrogen gas (H2), I think it takes energy. The breaking of them releases relatively little energy as well. But then you get to hydrogen fuel cells, where hydrogen under goes redox reaction with something and some other thing involving water, and all of a sudden you get a fuel cell that can potentially destroy Tasmania (for Americans, 2 Rhode Islands). Then there's also fusion reactions, where two hydrogen atoms literally fuse together to form helium. This could be our solution to the current fission problems, but we are still a fair while off.

2006-07-09 05:36:21 · answer #2 · answered by Anonymous · 0 0

I suppose you are speaking of nuclear fusion, correct? If so, here is your answer. You may have to do some math on your own, however.

A given weight of Deuterium (H2) also called Heavy Hydrogen, can produce about 4 times as much energy as the same weight of Uranium. Fissioning of 1 pound of (0.45 Kilograms) of Uranium produces as much energy as burning 1,140 short tons (1030 metric tons) or 2,280,000 pounds of coal. A short ton in America = 2000 pounds.

So to help you do the math:
If you have X pounds of Deuterium, it produces 4 times the energy of Uranium which produces as much energy as burning 1,140 short tons of Coal.

That means 1 pound of Deuterium = the same as fissioning 4 pounds of Uranium = Burning 4,560 Short tons or 9,120,000 pounds of coal.

1 short ton = 20,754,000 BTU's (BTU = British Thermal Units = A BTU is defined as the amount of heat required to raise the temperature of one pound avoirdupois of water by one degree Fahrenheit. 143 BTU is required to melt a pound of ice.)
(1 BTU = 1055 joules)

20,754,000 BTU = 21,869.63 megajoules (Megajoule = 1,000,000 Joules). 1 kilowatt-hour = 3,412 BTU.


1 joule = 1 watt second ( watt second = a unit of electrical energy equal to the work done when a current of one ampere passes through a resistance of one ohm for one second. )

1 ampere = 1 coulomb (6.28 x 1018 electrons) per second.

1 ohm = The unit of measure of electrical resistance. ( One volt will force a current of one ampere through a resistance of one ohm.)

1 volt = the force required to send one ampere of electrical current through a resistance of one ohm. It is analogous to water pressure in pounds per square inch. A unit of electrical pressure measuring the force or push of electricity. Volts x amps=watts. The terms potential, electromotive force (emf), and voltage are often used interchangeably. Also is = to performing one joule of work to move or separate one coulomb (6.25 x 1,018) of electrons. 1 Joule = 1/1055 or 0.000947867 BTU's.

1 watt = one joule per second, 1/746th horsepower. Volts x Amps x PF = Watts. (Note: For AC (AC = Alternate Current) circuits, PF (Power Factor) must be included.) Also = 107 ergs per second. Commonly used to define the rate of electricity consumption of an electric appliance. One watt of power is expended when one ampere of direct current flows through a resistance of one ohm.

Power factor = The ratio between Watts (Active or True power) and Volt-Amperes (Apparent power). The Power Factor has a value somewhere between zero and one. This ratio is generally expressed as a decimal fraction.The distribution utility has to provide equipment that will carry Amps, and if the Power Factor is poor (less than about 0.9), the distribution network is inefficient. A power factor of 1.00 is unity. A device such as a ballast( Ballast = device that controls currents in lamps) that measures 120 volts, 1 amp, and 60 watts has a power factor of 50% (volts x amps = 120 VA, therefore 60 watts/120 VA = 0.5).

1 erg = In terms of the joule, 1 erg equals 0.0000001 joule.

There is much more, but I think this is more than enough for what we want to do.

O.K. if we fuse 1 pound of Deuterium, that will produce 99,848,642.8 Megajoules of energy or 27,735,734.1 Kilowatt-hours.

1 watt-hour is equivalent to 1 watt of power used for 1 hour. This is equivalent to 3,600 joules. So, 1 kilowatt-hour is = to 1000 watts of power used for 1 hour and this is the equivalent of 3,600,000 joules.

You can use the above information to help you with figuring out the voltage and etc....

God Bless!!!

2006-07-09 05:05:55 · answer #3 · answered by Adyghe Ha'Yapheh-Phiyah 6 · 0 0

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