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10 answers

I would say a 45 degree angle. It is the median between upward force and forward force. You should get the maximum momentum from it.

2006-07-08 03:19:01 · answer #1 · answered by Anonymous · 0 0

first we need to look at what is happening here. When you throw something there are two portions of the motion, horizontal-distance and vertical-height. When you throw at less than 45 degrees you would have less than half of your velocity in the horizontal direction and the gravity due to acceleration would pull the thing thrown to the ground before it can reach its maximum distance. If you throw the object at an angle greater than 45 degrees then you will get the object ot go higher but you will have to sacrifice velocity in the horizontal direction. it will fly for a longer period of time but the longer flight time will not make up for the decrease in horizontal velocity and it will land short of the maximum. At 45 degrees you will ave enough vertical velocity to keep the object in the air for a reasonable amount of time and you will still have half of the velocity to carry the object horizontally. so regardless of the initial speed or the weight of the object the maximum distance horizontally is achieved with a 45 degree angle.

2006-07-08 10:50:47 · answer #2 · answered by tlets 2 · 0 0

Okay, from a high school physics point of view 45 degrees is the right answer.

However, this section is Engineering so we should give a better answer.

For starters there is air lift and drag effects. These will be greater near the ground.

Second as our range goes up the ground will curve away.

The first will tend to require the angle to be increased above 45 while the second will reduce the angle required.

Not an easy calculation. This is why during WWII the first computers were developed to produce aiming tables.

2006-07-08 17:02:51 · answer #3 · answered by DCA 1 · 0 0

I would venture to say a 45 degree, but the distance would depend on how much force is behind the object, and the density of the object itself.

Other angles may end up being a shorter distances anything below 45 degrees is too close to the ground and would fall sooner, and anything above 45 degrees would go higher not farther. you only have an angle window of 90 degrees.

2006-07-08 10:21:05 · answer #4 · answered by Dave 2 · 0 0

At an upward 45 degree angle it will travel the longest over all distance. If you mean the longest straight line distance from a starting point as measured on the ground then throwing it straight across the ground will get the longest distance.

2006-07-08 10:20:04 · answer #5 · answered by Martin S 7 · 0 0

according to the kinematics the range of a object thrown is depended on angle of projection and when the angle is 45 degrees the range is maximum.

2006-07-08 14:55:27 · answer #6 · answered by virgo_09_81 1 · 0 0

45 degree...But if you throw something on a sloped area you should adjust the angle ex if the area has 15 degree slope,you should throw 15+45=60 degree ;)

2006-07-08 10:18:44 · answer #7 · answered by Ricizki 1 · 0 0

45 degree.
A little bit of physics analysis gives that you need to find out when sin(A)*cos(A) will reach maximum. Because sin(A)*cos(A)=0.5*sin(2*A), it reaches maximum when A=45deg.

The following conditions are necessary to make this answer valid.

1. starting point and landing point are on the same flat horizontal surface (i.e., we are not talking about long-range missiles)
2. uniform gravity in the space under consideration
3. Air-drag is negligible.

2006-07-08 12:08:49 · answer #8 · answered by chong 1 · 0 0

I believe at 45 degrees.

2006-07-08 10:17:32 · answer #9 · answered by chemicalimbalance000 4 · 0 0

45 degrees.

im too lazy to write the explation here, basically take the range equation and differentiate it with respect to angle of projection and find its maxima.

(tell me f you need more detail...)

2006-07-08 10:18:07 · answer #10 · answered by shashank.chintalagiri 2 · 0 0

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