how to put this in c# 1+7/3^2?

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how to put this in c# 1+7/3^2?

2006-07-06 20:38:47 · 4 answers · asked by drew88 2 in Computers & Internet ➔ Programming & Design

4 answers

Depending on the order that you wanted your operations be carried out:

1 + 7 / System.Math.Pow(3, 2)

The first argument of Math.Pow is the base and the second is the exponent.

2006-07-06 22:23:11 · answer #1 · answered by punzki 2 · 0⤊ 0⤋

1+(7/3)^2 I may be wrong.

2006-07-06 20:46:25 · answer #2 · answered by Yahoo! Answerer 6 · 0⤊ 0⤋

Sorry buddy, tried to find out but in vain.

2006-07-06 20:57:09 · answer #3 · answered by Halle 4 · 0⤊ 0⤋

I think it iss like this
1+(7/pow(3,2));

2006-07-06 20:42:45 · answer #4 · answered by crackman 3 · 0⤊ 0⤋