(x^2+-4)(x^2+-4)?

Question

please explain what you did so i will understand it better

i want to simplify this and i alrady know what foil is

Answer 1

I'm assuming it's (x^2 + -4)(X^2 + -4)

OR (X^2-4)(X^2-4) (both are the same)

Do the FOIL method: Multiply the "First, outer, inner last."

- First means the first number in each parentheses.
- Inner means the second number in the first parentheses, and the first number in the second parentheses.
- Outer means the first number in the first parentheses, and the second number in the second parentheses.
- Last means the second numbers in each parentheses.

FIRST: X^2 x(times) X^2 = X^4


OUTER: X^2 x -4 = -4(X^2)


INNER: -4 x X^2 = -4(X^2)


LAST: -4 x -4 = 16



- Now you add them all together:

X^4 + (-4)(X^2) + (-4)(X^2) + 16


- Combine like terms:

(-4)(X^2) + (-4)(X^2) = (-8)(X^2)

- Rewrite it all with newly combined terms:

X^4 + (-8)(X^2) + 16

OR

X^4 - 8(X^2) + 16



(I think that's right! I hope....)

Answer 2

Using FOIL:

Multiply the "first" terms: x^2 * x^2 = x^(2 + 2) = x^4
Multiply the "outside" terms: x^2 * -4 = -4x^2
Multiply the "inside" terms: -4 * x^2 = -4x^2
Multiply the "last" terms: -4 * -4 = 16

Now, add it all together: x^4 - 4x^2 - 4x^2 + 16

=x^4 - 8x^2 + 16

Answer 3

ok...so u gotta use FOIL: F-first, O-outer, I-Inner, and L-last
step1: so the First terms are X^2 and X^2. wen mutiplied u get X^4
step2 partI: the outer terms are X^2(the one in first binomial) and -4(the -4 in the second binomial) so u multipy those and get -4X^2
step2 partII:u multiply the inner terms which are the-4 in the first binomial and the X^2 in the second binomial and u get -4X^2 yet again
step2 partIII: u had the O and the I which in ths case are -4X^2 and -4X^2 and u get -8X^2
step3:finaly u multiply the last terms which are -4 and -4 and u get+16
ur final answer shud be: X^4-4X^2+16

Answer 4

X^4 - 8X^2 + 16

actually that is equal to (x^2 - 4) ^2 which is
square the first term, twice the product of the two terms then square the last term

Answer 5

Use the algebraic identity (a+b)^2=a^2+2ab+b^2
here in place of a you have x^2 and in place of b you have -4
substituting or plugging in
(x^2+-4)(x^2+-4)=(x^2+-4)^2=(x^2)^2+2(x^2)(-4)+(-4)^2
=>x^4-8x^2+16

Answer 6

This problem used the F O I L method.
First-meaning the first in both parenthesis-x^2 multiplied by x^2,
= x^4
Outer-meaning the outer sets-x^2 multiplied by (-)4
=(-)4x^2
Inner-meaning the inner sets-(-)4 multiplied by x^2
=(-)4x^2
Last-meaning the last sets-(-)4 multiplied by (-)4
= 16
Put them together- x^4 -4x^2 -4x^2+16
Combine like terms- -4x^2-4x^2= -8x^2
Meaning x^4 -8x^2 + 16
This should be your answer.

Answer 7

1. Multiply first, outside, inside, last:

first. x^2 * x^2 = x^4
outside. x^2 * -4 = -4x^2
inside. -4 * x^2 = -4x^2
last. -4 * -4 = 16

2. Add it all together:
x^4 - 4x^2 - 4x^2 + 16

3. Reducing: x^4 -8x^2 + 16(final answer)

Hope this helps.

Answer 8

(x^2 +- 4)(x^2 +- 4)
If you wrote this correctly then there are four different equations:
(x^2 + 4)(x^2 + 4)
=x^4 + 4x^2 + 4x^2 + 16
=x^4 + 8x^2 + 16

(x^2 - 4)(x^2 + 4)
=x^4 + 4x^2 - 4x^2 -16
=x^4 - 16

(x^2 + 4)(x^2 - 4)
=x^4 - 4x^2 + 4x^2 - 16
=x^4 - 16

(x^2 - 4)(x^2 - 4)
=x^4 - 4x^2 - 4x^2 + 16
=x^4 -8x^2 + 16

Answer 9

(x^2+-4)^2

Answer 10

x^4-8x^2+16