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i got 3+7x but i just want to make sure im right

2006-07-06 16:42:44 · 17 answers · asked by Anonymous in Education & Reference Homework Help

17 answers

2x squared plus 5x plus 3

Multiply the first expressions: 1 * 3 = 3
Multiply the "outer" expressions: 1 * 2x = 2x
Multiply the "inner" expressions: x * 3 = 3x
Multiply the last expressions: x * 2x = 2x-squared (sorry about the bad notation on this!)

If you need help remembering this remember FOIL: First, Outer, Inner, Last.

Then, add all your results: 3 + 2x + 3x + 2x-squared.
That simplifies to 3 + 5x + 2x-squared.
In traditional form, it is reversed: 2x-squared + 5x + 3.

I hope that helps.

2006-07-06 16:51:10 · answer #1 · answered by BoredBookworm 5 · 0 1

Use FOIL again:

Multiply the "first" terms: 1 * 3 = 3
Multiply the "outside" terms: 1 * 2x = 2x
Multiply the "inside" terms: x * 3 =3x
Multiply the "last" terms: 2x * x =2x^2

Add it all together: 3 + 2x + 3x + 2x^2


=2x^2 + 5x + 3

2006-07-07 23:17:53 · answer #2 · answered by Anonymous · 0 0

2x^2 + 5x + 3 is the answer.


(1+x)(3+2x) =

(1*3) + (1*2x) + (x *3) + (x*2x) =

3 + 2x + 3x + 2x^2 =

3 + 5x + 2x^2 =

2x^2 + 5x + 3


^ 2 means "squared"
* means "times"

2006-07-06 23:47:11 · answer #3 · answered by G.V. 6 · 0 0

(x + 1)(2x + 3) [Pet peeve of mine to write the equation this way}
= 2x^2 + 3x + 2x + 3
= 2x^2 + 5x + 3

2006-07-06 23:49:43 · answer #4 · answered by Mike B 3 · 0 0

Isn't this just factor distribution, have u ever heard about the term FOIL when it comes to factroing.

3+2x+3x+2x^2....

Ans=2x^2+5x+3

2006-07-06 23:49:04 · answer #5 · answered by Jay D 2 · 0 0

(1+x)(3+2x)

= 3+2x+3x+2x^2

= 3+5x+2x^2

2006-07-07 09:25:26 · answer #6 · answered by bear 3 · 0 0

the answer is : 2x ^ 2 + 5x +3

2006-07-07 03:51:46 · answer #7 · answered by Sina 1 · 0 0

2x squared+5x+3

2006-07-06 23:47:19 · answer #8 · answered by silenthavens 2 · 0 0

(1 + x)(3 + 2x)
1*3=3, 1*2x=2x, x*3=3x, x*2x=2x(squared)
3 + 2x + 3x + 2x(squared)=2x(squared) + 5x + 3

2006-07-06 23:46:39 · answer #9 · answered by Anonymous · 0 0

(1+x)(3+2x)?

Apply (A+B)(C+D)=AC+AD+BC+BD

(1+x)(3+2x) = (1)(3) + (1)(2x) + (x)(3) + (x)(2x)
=3 + 2x + 3x + 2x^2
= 2x^2 + 5x +3


Good luck!

2006-07-07 00:06:17 · answer #10 · answered by lab_rat06 3 · 0 0

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