2x squared plus 5x plus 3
Multiply the first expressions: 1 * 3 = 3
Multiply the "outer" expressions: 1 * 2x = 2x
Multiply the "inner" expressions: x * 3 = 3x
Multiply the last expressions: x * 2x = 2x-squared (sorry about the bad notation on this!)
If you need help remembering this remember FOIL: First, Outer, Inner, Last.
Then, add all your results: 3 + 2x + 3x + 2x-squared.
That simplifies to 3 + 5x + 2x-squared.
In traditional form, it is reversed: 2x-squared + 5x + 3.
I hope that helps.
2006-07-06 16:51:10
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answer #1
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answered by BoredBookworm 5
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Use FOIL again:
Multiply the "first" terms: 1 * 3 = 3
Multiply the "outside" terms: 1 * 2x = 2x
Multiply the "inside" terms: x * 3 =3x
Multiply the "last" terms: 2x * x =2x^2
Add it all together: 3 + 2x + 3x + 2x^2
=2x^2 + 5x + 3
2006-07-07 23:17:53
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answer #2
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answered by Anonymous
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2x^2 + 5x + 3 is the answer.
(1+x)(3+2x) =
(1*3) + (1*2x) + (x *3) + (x*2x) =
3 + 2x + 3x + 2x^2 =
3 + 5x + 2x^2 =
2x^2 + 5x + 3
^ 2 means "squared"
* means "times"
2006-07-06 23:47:11
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answer #3
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answered by G.V. 6
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(x + 1)(2x + 3) [Pet peeve of mine to write the equation this way}
= 2x^2 + 3x + 2x + 3
= 2x^2 + 5x + 3
2006-07-06 23:49:43
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answer #4
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answered by Mike B 3
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Isn't this just factor distribution, have u ever heard about the term FOIL when it comes to factroing.
3+2x+3x+2x^2....
Ans=2x^2+5x+3
2006-07-06 23:49:04
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answer #5
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answered by Jay D 2
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(1+x)(3+2x)
= 3+2x+3x+2x^2
= 3+5x+2x^2
2006-07-07 09:25:26
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answer #6
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answered by bear 3
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the answer is : 2x ^ 2 + 5x +3
2006-07-07 03:51:46
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answer #7
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answered by Sina 1
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2x squared+5x+3
2006-07-06 23:47:19
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answer #8
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answered by silenthavens 2
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(1 + x)(3 + 2x)
1*3=3, 1*2x=2x, x*3=3x, x*2x=2x(squared)
3 + 2x + 3x + 2x(squared)=2x(squared) + 5x + 3
2006-07-06 23:46:39
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answer #9
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answered by Anonymous
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(1+x)(3+2x)?
Apply (A+B)(C+D)=AC+AD+BC+BD
(1+x)(3+2x) = (1)(3) + (1)(2x) + (x)(3) + (x)(2x)
=3 + 2x + 3x + 2x^2
= 2x^2 + 5x +3
Good luck!
2006-07-07 00:06:17
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answer #10
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answered by lab_rat06 3
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