2006-07-06 14:29:32 · 5 answers · asked by NewYorker32 1 in Science & Mathematics ➔ Mathematics
you could have tried to make that more clear, seeing how it isnt clear if the additions/subtractions are part of the powers or not, but i say the answer is -5.
assuming the problem is ((-2)^3) + 2((-2)^2) - 2(-2) -9
do the powers first, so it becomes (-8) + 2(4) -2 (-2) -9
then do the multiplications, so its (-8) + 8 - (-4) - 9
-8 and +8 cancel out, so u get 0 - (-4) - 9
Subtracting a negative makes it positive, so u have 4 - 9
4 - 9 = -5
2006-07-06 14:42:23 · answer #1 · answered by irish_payne 2 · 0⤊ 0⤋
f(-2)= -5
2006-07-06 21:35:36 · answer #2 · answered by Sim S 2 · 0⤊ 0⤋
f(x) = x^3 + 2x^2 - 2x - 9
f(-2) = (-2)^3 + 2(-2)^2 - 2(-2) - 9
f(-2) = -8 + 2(4) + 4 - 9
f(-2) = -8 + 8 + 4 - 9
f(-2) = 4 - 9
f(-2) = -5
2006-07-06 22:00:22 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
f(-2)=(-2)^3+2(-2)^2-2(-2)-9...... f(-2)= -8+8+4-9.........f(-2)= -5.......
-2f=-5.........f= -5:-2 .........f= 2,5
2006-07-06 22:54:14 · answer #4 · answered by Freesia 5 · 0⤊ 0⤋
why just use a calculator
2006-07-06 21:33:26 · answer #5 · answered by PSYCHO 2 · 0⤊ 0⤋