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What word, English Dictionary, describes the vector between two objects ,i.e., between the Earth & Moon? Thxs!

2006-07-06 11:04:39 · 9 answers · asked by twiglink 1 in Science & Mathematics Astronomy & Space

Specifically, the two(2) touching points of both ends of said vector are said to be what?

2006-07-17 02:36:23 · update #1

9 answers

will you explain the question?

a vector has direction and magnitude. forces can be described by vectors, but lots of other things can also.

2006-07-06 11:31:24 · answer #1 · answered by warm soapy water 5 · 3 0

uhhhhhhhhhhhhh, you can say distance, but that is not a vector, so the next best thing would be the position vector.

Basically, I need an arrow. So the position vector from the moon to the earth is exactly the negative of the position vector from the earth to the moon. The reason I can't use distance because the distance will stay the same. In fact, that is one of the definitions of distance. Distance should not change depending on where my ruler is. Distance from the earth to the moon is the same as from the moon ot the earth.

2006-07-06 11:44:09 · answer #2 · answered by The Prince 6 · 0 0

acceleration or centripetal force. The acceleration vector of an smaller object (the moon) orbiting a larger object (the Earth) always points toward the larger object. The velocity vector keeps the moon moving around the Earth instead of falling down.

http://www.astronomynotes.com/gravappl/s8.htm

2006-07-06 14:09:42 · answer #3 · answered by April C 3 · 0 0

Gravity

2006-07-06 11:11:42 · answer #4 · answered by PhysicsDude 7 · 0 0

No kidding. A straight line.

2006-07-15 09:20:33 · answer #5 · answered by thewordofgodisjesus 5 · 0 0

Not sure I understand your quesiton- can you rephrase this a little clearer?

2006-07-17 08:20:15 · answer #6 · answered by Anonymous · 0 0

balanced distance

2006-07-06 11:15:53 · answer #7 · answered by Fontonfrom 2 · 0 0

radius

2006-07-17 17:38:15 · answer #8 · answered by evi 2 · 0 0

Do you mean 'ORBIT'?

2006-07-06 11:09:18 · answer #9 · answered by Anonymous · 0 0

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