x to the second power plus 12x plus blank?

Question

complete the square. i'm guessing i'm supposed to solve for the blank, and my book really isn't helping. thanks.

Answer 1

I think you have x^2+12x + bl=0 were bl is your blank

if so it may get tricky.

This is a quadratic equation like ax^2+bx + c=0 where I assume in your case
a=1
b=12
c- blank

x1=(-b + SQRT(b^2-4ac)/2a SQRT square root of or to the power of or ^(1/2)
x2=(-b - SQRT(b^2-4ac)/2a

All nice but if b^2-4ac<0 you are in trouble unless you are into imaginary numbers .

So let us put the numbers in b^2-4ac>0 we have
b^2>4ac substituting numbers in we have
12^2>4c so c or your black should be
12^2>4c c<(12^2)4=144/4=36

So as long as your blank less then 36 you are safe.
To find out what is ‘blank’ you have to tell me the value of x otherwise x has any number of solutions.

Let me know if it helps

Answer 2

i think u do x^2+12x+y. (i subsitited y for the blank.)

x^2+12x+y
x^2+y= -12x
y= -12x-x^2

i think thats how you're suposed to do it, but im not sure