not sure how to do the integral sign thing but here is the problem
(x^2 - 4x +1)^2dx on the interval [1,3]
2006-07-06 07:48:04 · 5 answers · asked by 11 2 in Science & Mathematics ➔ Mathematics
well actually we were given a sheet of about 40 of these to do. These are just the ones i wasnt sure on. i would think 4 or five out of about 40 isnt too bad. :P
2006-07-06 08:56:55 · update #1
Rewrite:
(x^2-4x+1)(x^2-4x+1)dx
Expand:
(x^4-4x^3+x^2-4x^3+16x^2-4x+x^2-4x+1)dx
Combine Like terms:
(x^4-8X^3+18x^2-8X+1)dx
antiderrivative:
(1/5)x^5-2x^4+6x^3-4x^2+x+c
Plug in 3 and then plug in 1 and then subtract them
(15.6+c)-(1.2+c)
=14.4
2006-07-06 09:12:07 · answer #1 · answered by jvcc06 3 · 0⤊ 0⤋
I sure hate doing other people's homework... but I sure like getting 10 points. So:
(x^2 - 4x + 1)^2 = x^4 - 8x^3 + 18x^2 - 8x +1
(integral) THAT dx [1,3] =
[1,3] .2 x^5 - 2x^4 + 6x^3 - 4x^2 + x
=
14.4
There. That's the answer.
2006-07-06 09:13:13 · answer #2 · answered by Chx 2 · 0⤊ 0⤋
Do you just want us to do your homework? Why don't you post all the questions together?
2006-07-06 08:01:51 · answer #3 · answered by The Prince 6 · 0⤊ 0⤋
Yeah... Why must we do your homework for U???
2006-07-06 08:39:14 · answer #4 · answered by BDX 1 · 0⤊ 0⤋
14.4
2006-07-06 09:13:29 · answer #5 · answered by Olivia 4 · 0⤊ 0⤋