Events D, E, F and G are independent events, and P(D) = 0.4, P(E) = .6, P(F) = 0.3, and P(G) = 0.2. Find the?

Question

Events D, E, F and G are independent events, and P(D) = 0.4, P(E) = .6, P(F) = 0.3, and P(G) = 0.2. Find the probability of P(D and F and G).

Answer 1

of all occuring .2

Answer 2

Given events D, E, F, and G are independent i.e the probability of occurance of each event is not depends upon the probability of occurance of other event.

Given P(D) = 0.4
P(E) = 0.6
P(F) = 0.3
P(G) = 0.2

P (D and F and G) = P(D) x P(F) x P(G)
= 0.4 x 0.3 x 0.2
= 0.024

Therefore P (D and F and G) = 0.024


For more detailes and better understnding:

http://www.futureaccountant.com/probability/

http://www.schoolingkids.com/probability/

Answer 3

If the events are independent, the probability of
all will happen is the product of their probability.
P(D and F and G)= 0.4 * 0.3 * 0.2
The 'and' is the common part of the groups,
the 'or' is the sum of all the grops.
But beware: when you count 'or', you have to substract
the common parts, becouse you counted them more than
one time.

Answer 4

P(D and F and G) = 0.4 * 0.3 * 0.2 = 0.024