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9 answers

Since a byte has 8 bits, each group can store 2 to the 8*n as a number.

If you use a signed number, this would be half positive and half negative...

Example: 1 byte as unsigned would be from 0 to 255 (2^8=256); as a signed number this would be -128 thru 127 (0 has no negative value)
For 2 bytes, the same would be true, except use 2^16, so as unsigned you get 0 to 65536 or as signed -32768 to 32767, etc.

2006-07-06 06:42:32 · answer #1 · answered by N2FC 6 · 1 0

a byte contains 8 bits. As a binary number, a byte can reflect any number from 0-255, which gives you a maximum value per byte of 256 (assuming 0 is a valid value). In short, the minimum value for 1, 2, 3 or 4 bytes is 0. The maximum value for one byte is 256, for 2 it's 256x256, for three its 256x256x256 and for four it's 256x256x256x256

2006-07-06 06:49:35 · answer #2 · answered by antirion 5 · 0 0

it quite is a quadratic equation in a sort y = ax²-bx+c, the place a >0, so, the concavity of parabola is up ( parabola is smiling ), so, if the area is in reals, there is no longer a minimun, there's a optimal.you are able to calculate the y vertex straight away by employing (-delta)/(4a). for that reason: - delta = - (8*8 - 4*2*15) = fifty six 4a = 4*2 = 8 So the optimal (Y vertex ) is fifty six / 8 = 7 Or any incorrect way is: you will discover the x that correspond the y optimal(the fee of x for which max/min fee happens).so which you're able to do -b / 2a. for that reason: -b/2a = -(-8 /2*2 ) = 2 changing this fee in unique equation (2x²-8x+15), you will discover the Yvertex, it quite is 7, how we calculated till now.

2016-12-10 05:29:19 · answer #3 · answered by Anonymous · 0 0

1 byte is equal to 8 bits so the maximum binary no. would be 11111111(unsigned) = 255 for signed system the first bit is reserved to denote whether the no. is +ve or -ve....1 denotes a negative no. and 0 a +ve no... so for signed system the maximum no would be +177 and the minimum would be -177
for two bytes the max and min would be accordingly ...the first answer will tell u how to calculate it...

2006-07-06 07:01:23 · answer #4 · answered by vek14 3 · 0 0

each byte is composed of 8 bits either on or off (2 options)
1: is like 2^8 (two to the eighth power) or 256 combinations
2: is like 2^16 " sixteenth " or 65,536 combinations
3: is like 2 ^24 " twenty fourth" or 16,777,216 combinations
4: is like 2^32 " thirty second " or 4,294,967,296 combinations
this also represents the numeric value that goes converts out of all the bits being turned on.

2006-07-06 06:49:21 · answer #5 · answered by . 3 · 0 0

1 Byte --> -128..128
2 Bytes --> -32768..32768
3 Bytes --> -8388608..8388608
4 Bytes --> -2147483648..2147483648

2006-07-06 06:48:27 · answer #6 · answered by alaa_tm 3 · 0 0

1 byte -max.FF min 0
2 byte-max.FFFF min 0000
3 byte-max.FFFFFF min 000000
4 byte-max.FFFFFFF min.0000000

2006-07-06 06:48:01 · answer #7 · answered by siv_ece 1 · 0 0

its about the ram's that your computer allowed to hold because each computer designed different storage space.

2006-07-06 06:45:33 · answer #8 · answered by qaww1@sbcglobal.net 2 · 0 0

1
3
7
15

2006-07-06 06:44:30 · answer #9 · answered by Anonymous · 0 0

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