According to one investigator's model, the data are like 400 draws made at random from a large box. The null hypothesis says that the average of the box is 50; the alternative says it's more than 50. The data averaged out to 52.7 and the SD is 25. Compute z and P - What do you conclude?
2006-07-06 06:08:06 · 3 answers · asked by mindkontrol 2 in Science & Mathematics ➔ Mathematics
The SD is 25. I know, it's large.
2006-07-06 06:15:30 · update #1
z = (52.7 - 50) / (25/20)
z = 2.16
p = P(|z| > 2.16) = 2(.0154)
p = .0308
Reject the null hypothesis in favor of the alternative. Most likely, the actual average is greater than 50.
2006-07-06 06:35:04 · answer #1 · answered by itsverystrange 2 · 0⤊ 0⤋
that's a pretty big SD, are you sure its not 2.5 or .25
2006-07-06 06:13:44 · answer #2 · answered by dave 2 · 0⤊ 0⤋
z =5.34
Null hypothesis valid
2006-07-06 06:15:24 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋