2006-07-06 04:02:33 · 4 answers · asked by Gord McD 1 in Science & Mathematics ➔ Mathematics
It deends on how you mean "how many". There are ONLY THREE prime factors of 6336, namely 2, 3 and 11. However 2 divides it six times, and 3 divides it twice, so 6336 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 11, in which case you can say there are NINE prime factors. Sometimes people incorrectly speak of "factors" when they mean "divisors": for example 36 divides equally into 6336, so some people would call it a "factor" (which is not strictly true). In this case there are 38 different divisors, not counting 1 or 6336 itself.
2006-07-12 00:14:34 · answer #1 · answered by Anonymous · 0⤊ 0⤋
666
2006-07-06 04:06:10 · answer #2 · answered by Lapis Lazuli 2 · 0⤊ 0⤋
2x2x2x2x2x2x3x3x11is the prime factorization
and the sum is 29
2006-07-06 04:26:39 · answer #3 · answered by Brian K 1 · 0⤊ 0⤋
don't ask for homework help. do it yourself please.
2006-07-06 04:38:33 · answer #4 · answered by Anonymous · 0⤊ 0⤋