the perimeter of a rectangle is 276 centimeters. its length is 5 times its width. find its dimensions.?

Answer 1

2(l+b)=276
2(5w+w)=276 where w is the width
12w=276
w=13 cm
l=5w=65cm
Thats wat i call free points

Answer 2

In this question we need to find two unknown values; the length and the width of the rectangle. First we need to represent one of the unknown values using a letter.

Let us say that the width = w cm

Now, write the value of the length in terms of the width. Since it's 5 times as long as the width,

length = 5 x w = 5w cm

The formula for perimeter of a rectangle is
2(l + w) where l is length and w is width

Now we can form an equation for the question
Perimeter = 2 (5w + w)
276 = 2 x 6w
12w = 276
w = 276 / 12
= 23 cm

Therefore the width = 23 cm
length = 5 x width = 5 x 23 = 115 cm

Answer 3

2(l+b)=perimeter of a rectangle
let x be the width
therefore, 2(5x+x)=276 cm
2(6x)=276 cm
12x=276 cm
therefore x=276/12=23cm
so width=x=23 cm
length=5x=5*23=115 cm

Answer 4

Perimeter = 2(l + w) = 276 so (l + w) = 138
l = 5w so 6w = 138, w = 23 and l = 115
SO the dimensions are 115 cm x 23 cm

Answer 5

Let Width be = 'X' Cm
Length = 5 *X = 5X Cm

Perimeter = 2(L+B) = 2(X+5X) = 276
=> 12X = 276
=> X =276/12 =23
WIDTH = 23CM
LENGTH = 5*23=115CM

Answer 6

P = 2(l + w)
l = 5w

276 = 2(5w + w)
276 = 2(6w)
276 = 12w
w = 23

l = 5(23)
l = 115

Width = 23cm
Length = 115cm

Answer 7

Half perimeter is 276/2=138cms
breadth = x cms
length= 5x cms
138/6 = 23
if breadth is 23 cms length is is 23x5=115cms

Answer 8

P=2L+2W
276=2L+2W

Since L=5W...
276=2(5W)+2W
276=10W+2W
276=12W
276/12=12W/12
23=W
L=5W, so L=115

Answer 9

length x;
width y;

2x + 2y = 276;
x+y=138;
x=5y;
6y=138;
y=23;
x=115;
length 115;
width 23;

Answer 10

let width be x, so length is 5x.
perimeter is 2(5x+x) i.e. 12x or 276, so x=23
and so width is 23 and length is 5x or 115.

Answer 11

p=2[l+b]
276=2[5b+b]
276=2*6b
b=276/12
b=23cms

l=5b
l=23*5
l=115

so l=115cms and b=23cms