If it is to stand for 80 miiligrams of powder, then why is an M-90 less powerful. An M-100 is very weak and definitely has less powder than an M-80.
2006-07-06 01:35:26 · 4 answers · asked by Veccster 2 in Society & Culture ➔ Holidays ➔ Independence Day
M-80 is the American army designation for it, not the weight of the powder.. it was used as a rifle fire simulator and booby trap training device. 3 grams of flashpowder was a common charge, which varied from one manufacturer to another. the real thing was taken off the market decades ago, and the M-90 and M-100 popper devices sold today are feeble toys, containing 50 milligrams or .789 'grain' of flashpowder. (7,000 grains = 1 lb.) the real M-80's could cause serious injuries or property damage, and have been illegal in the USA since 1966.
And contrary to popular belief, the M-80 is _not_ as powerful as dynamite or TNT. that's pure malarkey.
The 'M' (Military) classification doesn't pertain to the M-90, M-100, M-8000 and so on, these aren't used by the military for any purpose, they're just advertising gimmicks for the civilian junk sold by fireworks vendors.
2006-07-06 01:44:37 · answer #1 · answered by Anonymous · 1⤊ 0⤋
I believe they are weighed in "grains" as the powder of a bullet is. Anyway, M80s use flash powder, which is also used in firecrackers. It is very fine,(like babypowder) and faster burning. The others use gun powder which is coarser and slower burning.
2006-07-06 08:45:49 · answer #2 · answered by MetalTeK 2 · 0⤊ 0⤋
i was always told that an m80 was 1/8th the size of a stick of TNT and m100 would 1/10... this is what i was told as a kid dont know for sure
2006-07-06 16:16:21 · answer #3 · answered by Grin Reeper 5 · 0⤊ 0⤋
It's just an advertising gimmick. It doesn't mean anything.
2006-07-06 08:49:31 · answer #4 · answered by grizzly_r 4 · 0⤊ 0⤋