2006-07-04 23:37:51 · 33 answers · asked by Ryan P 1 in Science & Mathematics ➔ Mathematics
i
where i is the imaginary number in complex number system
2006-07-04 23:39:33 · answer #1 · answered by Arun 2 · 0⤊ 0⤋
1
2006-07-04 23:38:59 · answer #2 · answered by hello 3 · 0⤊ 0⤋
Negative integers are not perfect squares due to the fact that the square root of a number is any number that the product of a number multiplied by itself. IE the square root of 81 is 9 or -9. There is no way to multiply a number times itself and get a negative number.
2006-07-04 23:41:13 · answer #3 · answered by zaffaris 5 · 0⤊ 0⤋
As many have answered, the square root of -1 is i, where i stands for imaginary. However, contrary to what many here have said, i IS a real and valid number (but it is not part of the "real" set). The name "imaginary" does not mean that the number does not exist. It is just a name to separate these types of numbers from other types of numbers. Many branches of physics deal with imaginary numbers, so to say that they do not 'really' exist misses the point.
2006-07-05 01:36:15 · answer #4 · answered by Michael M 2 · 0⤊ 0⤋
it doesn't exist. the square root of 1 is 1, but you cannot have a negative sqaure root because when you multiply a postivie number with itself you get a postivie number (3 x 3 = 9) but when you muliply a negative number with itself, you ALSO get a POSTIVE number back (-3 x -3 = 9). so therefore the square root of minus 1 does not exist!!
2006-07-04 23:55:01 · answer #5 · answered by Anonymous · 0⤊ 0⤋
actually, there is no real answer for square root of minus 1, cos every number, whether negative of positive, will be positive if we square it.
but, in mathematics, there is a special definition for square root of -1, it's called imaginary character [imaginary numbers], and the answer of square root of -1 is i [written in italic]
2006-07-05 04:22:09 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the square root of minus one is any number which when multiplied by itself the answer is -1.
In mathematics the square root of any negative number is always complex number. it has been taken as a standard that the squareroot of -1 is "i".
2006-07-05 00:37:53 · answer #7 · answered by innopacho 2 · 0⤊ 0⤋
An imaginary number denoted by the letter "i"
Since multiplied to itself results in a -1 which can be thought of as a vector that goes in a direction opposite to plus 1 - i.e turning by 180 degrees - then multiplying a positive number turns the vector along the x axis by 90 (counterclockwise) and aligns the result along the y axis.
2006-07-04 23:42:12 · answer #8 · answered by dont try 2 · 0⤊ 0⤋
The number system is divided into real and imaginary numbers. The square root of -1 is the imaginary number i. There is an entire branch of mathematics devoted to imaginary numbers. It is used extensively in vector mathematics, and real world application is mostly in the field of electronics.
2006-07-04 23:57:44 · answer #9 · answered by kkspeakssense 1 · 0⤊ 0⤋
It's an impossibility, but in maths, it is termed as "i" or "j".
Think of your question this way: what number can u square to get minus 1???
2006-07-04 23:41:23 · answer #10 · answered by Saaber 1 · 0⤊ 0⤋
minus 2.
2006-07-05 01:20:24 · answer #11 · answered by iamlsu 3 · 0⤊ 0⤋