The diameter of circle is 3 cm.AB and MN are two diameters such that MN is perpendicular to AB.In addition,CG is perpendicular to AB such that AE:EB=1:2 and DF is perpendicular to MN such that NL:LM=1:2.The length of DH in cm is
(a) 2*sqrt(2)-1
(b) [2*sqrt(2)-1]/2
(c) [3*sqrt(2)-1]/2
(d) [2*sqrt(2)-1]/3
2006-07-04 23:14:06 · 4 answers · asked by Rohit C 3 in Science & Mathematics ➔ Mathematics
You have not defined the question adequately. You define AB, MN, CG and DF but nowhere do you tell us about E, H and L. One may guess that E is on the circumference where CG interesects the circle, and likewise that L is on the circumference where DF intersects the circle, but that still doesn't help us know where you intend H to be!
2006-07-11 20:55:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Hey Rohit,
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Im Kirat
2006-07-05 06:20:31 · answer #2 · answered by pantherapardus1992 1 · 0⤊ 0⤋
Wheres that H come from?
and you never specified that E and L are the points where the lines cross each other.. so there is no way i can aswer this
2006-07-05 06:18:56 · answer #3 · answered by kalkmat 3 · 0⤊ 0⤋
Something seems to be missing. A diagram would have been of great help.
2006-07-05 06:45:52 · answer #4 · answered by nayanmange 4 · 0⤊ 0⤋