If x=[(16^3)+(17^3)+(18^3)+(19^3)],then x divided by 70 leaves a remainder of (a)0,(b)1,(c)69 or (d)35?

Question

If x=[(16^3)+(17^3)+(18^3)+(19^3)],then x divided by 70 leaves a remainder of
(a) 0
(b) 1
(c) 69
(d) 35

Answer 1

X=(16^3)+(17^3)+(18^3)+(19^3)+....
X=[Summation (n^3)] , n>=16 -> n=infinity , n is integer...

This is an infinite expression which you can't specify the remainder value...

but if you mean :

X=(16^3)+(17^3)+(18^3)+(19^3)-> Finite expression = 21700
21700/70 = 310 ->remainder = 0...

Answer 2

Your expression for the sum implies that the series is infinite. If that is so, then there is probably no definite answer.

Answer 3

a