can you express sum of two squares as sum of another two squares?
2006-07-04 19:45:11 · 8 answers · asked by rajesh bhowmick 2 in Science & Mathematics ➔ Mathematics
7 ^ (2) +145 ^ (2) = 25 ^ (2) + 143 ^ (2)
2006-07-04 20:36:29 · update #1
there is balances. the right and the left side have the same answer. and it is known as phytagoras theorem.you can prove it by using this method. and amazingly you will find that your question is obey the phytagoras theorem.
2006-07-04 21:15:22 · answer #1 · answered by Anonymous · 1⤊ 2⤋
Another example is
5^2 + 5^2 = 25 + 25 = 50 = 1 + 49 = 1^2 + 7^2
2006-07-05 20:32:44 · answer #2 · answered by ymail493 5 · 0⤊ 0⤋
Assuming we are not restricted to whole numbers
3*3 + 4*4 = 0*0 + 5*5
Assuming we are not restricted to positive numbers
3*3 + 4*4 = (-3)*(-3)+(-4)*(-4)
There are probably more examples involving irrationals and imaginary numbers.
Can you give us a domain to work in such as +ve integers?
2006-07-05 03:03:38 · answer #3 · answered by Anonymous · 0⤊ 0⤋
let a^2+b^2=c
then (sq rt(c-1))^2+1^2=c
2006-07-05 03:08:23 · answer #4 · answered by sgm 1 · 0⤊ 0⤋
it depends on the conditions
if i use only natural numbers/ integers it is not possible
(ah! now it occurs to me- replace the numbers by their negatives)
if i use real numbers - yes it is possible
2006-07-05 03:07:16 · answer #5 · answered by Srikanth 2 · 0⤊ 0⤋
yes do the math
2006-07-05 03:09:16 · answer #6 · answered by Anonymous · 0⤊ 0⤋
ab^4=cd^4....? I don't know, I am horrible at math.
2006-07-05 02:55:40 · answer #7 · answered by ericsrei 2 · 0⤊ 0⤋
why not??? A= (sqrt(A+b))^2 -(sqrt(b))^2 and b can be any number.
2006-07-05 13:46:47 · answer #8 · answered by Anonymous · 0⤊ 0⤋