Let f(x) = x/(x - 1) g(x) = (x - 1)/x h(x) = 1/(x - 1) . Then (f - h)(x) =?

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Let f(x) = x/(x - 1) g(x) = (x - 1)/x h(x) = 1/(x - 1) . Then (f - h)(x) =?

2006-07-04 18:16:04 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help

4 answers

i think it's X^2-1/x

2006-07-04 18:20:34 · answer #1 · answered by Freddy 2 · 0⤊ 0⤋

(f-h)(x) = f(x) - h(x) = x/(x-1) - 1/(x-1) = (x-1)/(x-1) = 1.

2006-07-05 01:20:50 · answer #2 · answered by anonymous 7 · 0⤊ 0⤋

In these type of functions you should do the function associated with the given function.For example
If f(x) = 2x, g(x) = 43
Then (f-g)(x) = 2x - 43. This is the basic principle involved in this problem.
Comming to your question,
(f-h)(x) = {x/(x - 1) } - { 1/(x - 1) } = (x-1) / (x-1) = 1
Here there is no need of the function g(x)
Therefore (f-h)(x) is a constant function

2006-07-07 06:18:18 · answer #3 · answered by Sherlock Holmes 6 · 0⤊ 0⤋

ans is 1

2006-07-05 01:29:50 · answer #4 · answered by spider 2 · 0⤊ 0⤋