2006-07-04 18:14:07 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Let x = jim's age
5x - 3 = 3x + 37
Solve for x.
Subtract 3x from each side
2x - 3 = 37
Add 3 to each side
2x = 40
Divide each side by 2
x = 20
2006-07-04 18:16:48 · answer #1 · answered by MsMath 7 · 1⤊ 1⤋
57
let jims age be x
so 5x-3 = 3(x+37)
solve
x=57
2006-07-04 18:19:46 · answer #2 · answered by plzselectanotherone 2 · 0⤊ 0⤋
Jim is 20 years old.
2006-07-04 18:18:21 · answer #3 · answered by audrey 2 · 0⤊ 0⤋
5J - 3 = 3J + 37 (Problem)
5J = 3J + 40 (Get numbers all on one side)
2J = 40 (Get variables all on other side)
J = 20 (Do the simple math)
Now does this work? Lets verify...
5 * 20 - 3 = 3 * 20 + 37 (Problem with answer replacing variable)
100 - 3 = 60 + 37 (pMdas)
97 = 97 (pmdAS)
Jim is 20. ( Your final answer)
2006-07-04 18:40:00 · answer #4 · answered by technical_13 4 · 0⤊ 0⤋
Jim is 20, I would write out the steps for you, but I did this one in my head.
2006-07-04 18:20:58 · answer #5 · answered by Kipper 7 · 0⤊ 0⤋
X is Jim's age
5X-3=3X=37
2X=40
X=20
Jim is 20 years old
2006-07-04 19:31:13 · answer #6 · answered by wormhole 2 · 0⤊ 0⤋
jim's age is 20
2006-07-04 18:43:22 · answer #7 · answered by abhinav 2 · 0⤊ 0⤋
let jims age be x
then 5x-3=3(x+37)
2x=114
x=57
he is 57 yrs old
2006-07-04 18:26:13 · answer #8 · answered by priya 2 · 0⤊ 0⤋
20 years old
2006-07-04 18:26:56 · answer #9 · answered by Anonymous · 0⤊ 0⤋
3x +37 = 5x-3
-3x -3x
37 = 2x-3
+3 +3
40 = x
he is 40 years old.
2006-07-04 18:21:29 · answer #10 · answered by mandeezy26 2 · 0⤊ 0⤋