there'll be no yahoo answers when you take your exam on this.
2006-07-04 17:55:08
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answer #1
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answered by pyg 4
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7 - 2[2x-2]+x-8=6
=> 7 - 4x + 4 +x -8 =6
=> 3 - 3x=6
=> x=-1
2006-07-05 01:47:49
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answer #2
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answered by abhinav 2
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7-2[4-(6-2x)] - (8- x) =6 - Original equation
7-2[4-6+2x] - 8+x=6 - multiply or distribute into parenthesis
7-2[-2+2x] -8+x=6 - add/sub within brackets
7+4-4x-8+x=6 - disribute into brackets
3-3x=6 - Collect like terms
-3x=3 - - the three to both sides
x=-1 - divide by -3 on both sides
2006-07-05 02:38:25
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answer #3
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answered by Anonymous
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7-2[4 - 6 + 2x] - 8 + x = 6
7 - 2 (-2+2x) -8 +x = 6
7 + 4 - 4x - 8 + x = 6
3 - 3x = 6
3x = -3
x= -1
2006-07-05 01:08:51
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answer #4
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answered by Hardik 2
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x= -1
2006-07-05 00:57:01
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answer #5
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answered by coreng 1
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x=-1
2006-07-05 00:59:15
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answer #6
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answered by SueInBoston 3
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7-2(-2+2x)-8+x=6
7 +4-4x-8+x=6
3+3x=6
-3x=3
x=-1
do your own homework yahoo wont be here during your tests
2006-07-05 01:02:12
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answer #7
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answered by Jack Kerouac 6
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-1
2006-07-05 01:00:50
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answer #8
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answered by Rohit C 3
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7+4-4x-8+x=6
-3-3x=0
x=-1
2006-07-05 01:06:20
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answer #9
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answered by sanjeewa 4
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7-2[4 - (6-2x) ] - (8-x) = 6
7- [8-(12-4x)] - (8-x) =6
7- [8+-12 +4x] - (8-x)=6
7-[-4 +4x] - (8-x)=6
7+ 4 - 4x -8 +x =6
-3x=3
x=-1
2006-07-05 00:54:42
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answer #10
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answered by tom_a_hawk12 4
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7 - 2[4 -(6 - 2x)] - ( 8 - x ) = 6
or,7+4-4x-8+x=6
or,-3x=3
or,x=-1
2006-07-05 01:02:57
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answer #11
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answered by dipanwita k 1
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