a3b2c-a2b3c-a2bc3=?

0 ⤊

2006-07-04 16:43:33 · 4 answers · asked by marcella i 1 in Science & Mathematics ➔ Mathematics

You could factor this. I assume that's what you want to do here. It factors as:

a^2bc(ab - b^2 - c^2)

2006-07-04 16:47:32 · answer #1 · answered by mathsmart 4 · 0⤊ 0⤋

Okay.. I'm definitely not doing your homework for you.

Just combine like terms. How hard is that to match up letters and numbers?

2006-07-04 16:47:01 · answer #2 · answered by instantly_oatmeal 7 · 0⤊ 0⤋

a3b2c-a2b3c-a2bc3
= 6abc - 6abc - 6abc
= - 6abc

2006-07-04 16:49:40 · answer #3 · answered by tkquestion 7 · 0⤊ 0⤋

a2bc(ab-b2-c2)

if not
6abc-6abc-6abc
6(abc-abc-abc)
6(abc-2abc)
-6abc

haaahaahaa
heeheeeheee

2006-07-05 02:35:00 · answer #4 · answered by koolgrl87 3 · 0⤊ 0⤋