2006-07-04 15:58:14 · 8 answers · asked by kp.eric 2 in Science & Mathematics ➔ Physics
I can't believe this, this exact question was on my Physics final: it is 1/4 of the original, because the force of gravity is inversely proportional to the square of the distance.
2006-07-04 16:01:59 · answer #1 · answered by Chris 3 · 0⤊ 0⤋
Distance doubled lessen the force of gravity because of the other forces it allows in the middle.
2006-07-04 23:25:42 · answer #2 · answered by Axiom 3 · 0⤊ 0⤋
if you want to calculate the force one body feels use
-G m / r^2
where m is the mass of the "other" body and r is the distance between them. So basically if you double the distance between the two, the force is a quarter (1/4) of whatever you started with.
the force is INVERSELY proportional to the square of the distance between them
2006-07-04 23:07:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋
it's one fourth of the original. Force of gravity in inversely proportional to distance squared.
2006-07-05 00:05:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Cris just stole my answer! But yea the gravitational force formula between 2 object is
F = - GMm / r^2 (V)
M is the large mass
m smaller mass
r is the distance
G is the gravitational field
V is the directional vector between the two
2006-07-04 23:11:43 · answer #5 · answered by Enchantress 3 · 0⤊ 0⤋
if i remember right, as the distance is double the force is four times as less. F = G(m1m2)/r2. R is the distance.
2006-07-04 23:04:38 · answer #6 · answered by mytbouf21 2 · 0⤊ 0⤋
It decreases with distance
2006-07-04 23:01:34 · answer #7 · answered by Bear Naked 6 · 0⤊ 0⤋
It doesn't change.
2006-07-05 00:09:26 · answer #8 · answered by cord v 1 · 0⤊ 0⤋