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2006-07-04 14:46:45 · 8 answers · asked by Poncho Rio 4 in Science & Mathematics Mathematics

8 answers

For those of us that don't even know what the Reimann hypothesis is. John nash from beutiful mind is hindered by his medication attempts to improve upon the Reimann Hypothesis.

Good Luck on any attempts, if john nash can't do it I can't either
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First published in Riemann's groundbreaking 1859 paper (Riemann 1859), the Riemann hypothesis is a deep mathematical conjecture which states that the nontrivial Riemann zeta function zeros, i.e., the values of other than -2, -4, -6, ... such that (where is the Riemann zeta function) all lie on the "critical line" (where denotes the real part of ).

A more general statement known as the generalized Riemann hypothesis conjectures that neither the Riemann zeta function nor any Dirichlet L-series has a zero with real part larger than 1/2.

Legend holds that the copy of Riemann's collected works found in Hurwitz's library after his death would automatically fall open to the page on which the Riemann hypothesis was stated (Edwards 2001, p. ix).

While it was long believed that Riemann's hypothesis was the result of deep intuition on the part of Riemann , an examination of his papers by C. L. Siegel showed that Riemann had made detailed numerical calculations of small zeros of the Riemann zeta function to several decimal digits (Granville 2002; Borwein and Borwein 2003, p. 68).

The Riemann hypothesis has thus far resisted all attempts to prove it. Stieltjes (1885) published a note claiming to have proved the Mertens conjecture with , a result stronger than the Riemann hypothesis and from which it would have followed. However, the proof itself was never published, nor was it found in Stieltjes papers following his death, so it is strongly believed his claim to have possessed such a proof was erroneous (Derbyshire 2004, pp. 160-161 and 250). In the late 1940s, H. Rademacher's erroneous proof of the falsehood of Riemann's hypothesis was reported in Time magazine, even after a flaw in the proof had been unearthed by Siegel (Borwein and Bailey 2003, p. 97; Conrey 2003). de Branges has written a number of papers discussing a potential approach to the generalized Riemann hypothesis (de Branges 1986, 1992, 1994) and in fact claiming to prove the generalized Riemann hypothesis (de Branges 2003, 2004; Boutin 2004), but no actual proofs seem to be present in these papers. Furthermore, Conrey and Li (1998) prove a counterexample to de Branges's approach, which essentially means that theory developed by de Branges is not viable.

Proof of the Riemann hypothesis is number 8 of Hilbert's problems and number 1 of Smale's problems.

In 2000, the Clay Mathematics Institute (http://www.claymath.org/) offered a $1 million prize (http://www.claymath.org/millennium/Rules_etc/) for proof of the Riemann hypothesis. Interestingly, disproof of the Riemann hypothesis (e.g., by using a computer to actually find a zero off the critical line), does not earn the $1 million award.

In the Season 1 episode "Prime Suspect" (2005) of the television crime drama NUMB3RS, math genius Charlie Eppes realizes that character Ethan's daughter has been kidnapped because he is close to solving the Riemann hypothesis, which allegedly would allow the perpetrators to break essentially all internet security.

The Riemann hypothesis was computationally tested and found to be true for the first 200000001 zeros by Brent et al. (1982), covering zeros in the region ). S. Wedeniwski used ZetaGrid (http://www.zetagrid.net/) to prove that the first trillion () nontrivial zeros lie on the critical line. Gourdon (2004) then used a faster method by Odlyzko and Schönhage to verify that the first ten trillion () nontrivial zeros of the function lie on the critical line. This computation verifies that the Riemann hypothesis is true at least for all less than 2.4 trillion. These results are summarized in the following table, where indicates a gram point.

source
Brent et al. (1982)
Wedeniwski/ZetaGrid
Gourdon (2004)

The Riemann hypothesis is equivalent to the statement that all the zeros of the Dirichlet eta function (a.k.a. the alternating zeta function)

(1)

falling in the critical strip lie on the critical line .

Wiener showed that the prime number theorem is literally equivalent to the assertion that the Riemann zeta function has no zeros on (Hardy 1999, pp. 34 and 58-60; Havil 2003, p. 195).

In 1914, Hardy proved that an infinite number of values for can be found for which and (Havil 2003, p. 213). However, it is not known if all nontrivial roots satisfy . Selberg (1942) showed that a positive proportion of the nontrivial zeros lie on the critical line, and Conrey (1989) this to at least 40% (Havil 2003, p. 213).

André Weil proved the Riemann hypothesis to be true for field functions (Weil 1948, Eichler 1966, Ball and Coxeter 1987). In 1974, Levinson (1974ab) showed that at least 1/3 of the roots must lie on the critical line (Le Lionnais 1983), a result which has since been sharpened to 40% (Vardi 1991, p. 142). It is known that the zeros are symmetrically placed about the line . This follows from the fact that, for all complex numbers ,

1. and the complex conjugate are symmetrically placed about this line.

2. From the definition (1), the Riemann zeta function satisfies , so that if is a zero, so is , since then .

It is also known that the nontrivial zeros are symmetrically placed about the critical line , a result which follows from the functional equation and the symmetry about the line . For if is a nontrivial zero, then is also a zero (by the functional equation), and then is another zero. But and are symmetrically placed about the line , since , and if , then . The Riemann hypothesis is equivalent to , where is the de Bruijn-Newman constant (Csordas et al. 1994). It is also equivalent to the assertion that for some constant ,

(2)

where is the logarithmic integral and is the prime counting function (Wagon 1991). Another equivalent form states that

(3)

where

(4)

where is the fractional part (Balazard and Saias 2000).


By modifying a criterion of Robin (1984), Lagarias (2000) showed that the Riemann hypothesis is equivalent to the statement that

(5)

for all , with equality only for , where is a harmonic number and is the divisor function (Havil 2003, p. 207). The plots above show these two functions (left plot) and their difference (right plot) for up to 1000.

There is also a finite analog of the Riemann hypothesis concerning the location of zeros for function fields defined by equations such as

(6)

This hypothesis, developed by Weil, is analogous to the usual Riemann hypothesis. The number of solutions for the particular cases , (3,3), (4,4), and (2,4) were known to Gauss .

According to Fields medalist Enrico Bombieri, "The failure of the Riemann hypothesis would create havoc in the distribution of prime numbers" (Havil 2003, p. 205).

2006-07-04 14:54:04 · answer #1 · answered by researchtissue 5 · 0 1

Riemann?

2006-07-04 21:49:54 · answer #2 · answered by Anonymous · 0 0

Put in your search engine "Riemann hypothesis" and follow the list .
YOUR ANSWER is in there...
It will take you some time but there is much stuff you can work with.
HERE the space is too limited.:)
GOOD LUCK.

2006-07-05 00:04:02 · answer #3 · answered by UncleGeorge 4 · 0 0

Take a look at the papers on this webpage:

"http://www.math.purdue.edu/~branges/site//Papers"

I haven't read through them (not many have), but it is an established professor of mathematics purporting a proof.

Enjoy,

Steven

p.s. "Apology" means "explanation" in de Branges' context.

2006-07-05 01:04:29 · answer #4 · answered by Steven S 3 · 0 0

I think it is unknown, for any , whether each of the possible digits in the base expansion of (or , etc) occur infinitely often.

2006-07-04 21:55:48 · answer #5 · answered by Anonymous · 0 0

I wish, the million would come in handy.

2006-07-04 22:12:04 · answer #6 · answered by Triple M 3 · 0 0

do the math

2006-07-05 03:23:45 · answer #7 · answered by Anonymous · 0 0

I KNOW HOW, SADLY MY PROOF DOESNT FIT HERE.....

2006-07-04 23:26:24 · answer #8 · answered by locomexican89 3 · 1 0

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