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2006-07-04 11:54:55 · 4 answers · asked by tq 3 in Science & Mathematics Mathematics

4 answers

dy/dx=7^x*ln7

2006-07-04 11:58:06 · answer #1 · answered by zakizero 1 · 3 2

Take logarithm of both sides w.r.t. base 'e'.
ln(y) = ln(7^x) = x*ln(7)

Differentiating both sides w.r.t. 'x'
(1/y)*(dy/dx) = 1*ln(7)
or dy/dx = y*ln(7)
or dy/dx = (7^x)*ln(7) [since y = 7^x]

2006-07-04 21:09:49 · answer #2 · answered by psbhowmick 6 · 0 0

dy/dx =(7^x)(ln 7)

2006-07-04 19:01:06 · answer #3 · answered by ap chem student 2 · 0 0

The derivative of a^x is a^x (ln a)

2006-07-04 18:58:22 · answer #4 · answered by mathematician 7 · 0 0

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