2006-07-04 11:49:53 · 8 answers · asked by tq 3 in Science & Mathematics ➔ Mathematics
dy/dx=e^x+cos(x)+e^xcos(x)+e^xsin(x)
2006-07-04 11:54:43 · answer #1 · answered by jvcc06 3 · 4⤊ 1⤋
The derivative of e^x is e^x. The derivative of sin(x) is cos(x). The third term needs the product rule. Seems easy enough.
2006-07-04 11:57:46 · answer #2 · answered by mathematician 7 · 0⤊ 0⤋
Convert each difficulty in terms of sin x and cos x: tan x * (sin x + cot x cos x) = (sin x / cos x) * (sin x + cos^2 x / sin x) = (sin^2 x / cos x) + cos x = (sin^2 x + cos^2 x) / cos x = a million / cos x = sec x
2016-12-10 04:34:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
im not sure how the problem is meant to read
if it's y= e^x + sinx + e^(x sinx) then it's
dy/dx = e^x + cosx + (x cosx + sinx)e^(x sinx)
if it's y= e^x + sinx +(e^x)(sinx) then it's
dy/dx = e^x + cosx + (e^x)(cosx) + (sinx)(e^x)
2006-07-04 11:58:33 · answer #4 · answered by ap chem student 2 · 0⤊ 0⤋
dy/dx = e^x + cos x + e^x cosx + e ^ x sinx
2006-07-04 11:57:35 · answer #5 · answered by M 1 · 0⤊ 0⤋
i think its 9 but im usually not correct with some of this
2006-07-04 11:53:11 · answer #6 · answered by Anonymous · 0⤊ 0⤋
dy/dx=e^x+cosx+e^x*cosx+e^x*sinx
2006-07-04 11:56:20 · answer #7 · answered by zakizero 1 · 0⤊ 0⤋
ah, not me.
2006-07-04 11:52:48 · answer #8 · answered by Anry 7 · 0⤊ 0⤋