projectile motion....?

Question

The equation of a projectile is y=ax - bx^2. What will be the horizontal range?

Answer 1

for the range, you will need to know the velocity and the angle at which it is fired at that elocity..if u know those then the rangeis given by:

Range =[v^2sin2(angle)]/g

whrere g is acceleration due to gravity

Answer 2

The flight time x is obtained by solving this for y=0, which is what y will be when the projectile hits the ground. The more interesting part of the problem is to calculate a and b from the launch velocity and angle of the projectile, and thus to determine the range. Let w be the launch angle and z be the velocity. The vertical component of the launch velocity will be z sin w; in the original equation, this is a. The horizontal component will be z cos w; this multiplied by the flight time x will give the downrange distance.

Answer 3

the equation of a projectile is d=1/2at^2+vit. horizontal range is where you have whatever acceleration backwards from air resistance or another force and vi as the initial horizontal velocity. you need to get that from the trig functions of the angle of launch and the initial velocity out of the launcher.