2006-07-04 07:01:52 · 5 answers · asked by Anonymous in Sports ➔ Baseball
Each divisional winner (team with the best regular season record in eac division) automatically goes to the playoffs as well as the team with the best record that did not win their division (wild card team). In the case of a tie, the tied teams will play a 163rd regular season game to decide which team goes to the playoff.
The first round of playoffs will match up the divisional winner with the best record against the wild card team unless they are form the same division. In this case, the division winner with the best record will face the division winner with the worst record. In either case, the other two teams will face each other.
The first round is a best of 5 series - first team to win 3 games advances to the next round. The team with the better regular season record gets home field advantage (2 games home, 2 on the road, 1 at home), unless the team with the better record is the wild card team, they will always lose home field advantage regardless of record. This round is referred to as the divsional series (ALDS and NLDS).
Next round is the league championshop series which determines the AL and NL champions and who makes it to the World Series. Again, team with better record gets home field advantage unless they are the wild card team. This is a best of 7 games series where team with the home field advantage plays: 2 at home, 3 on the road, and 2 at home.
The final round is the World Series. Home field advantage is determined by the outcome of the All-Star game played in July. The league that wins that game gets home field advantage. Also, since the AL and NL have slightly different rules (DH vs pitcher batting), the rules in effect reflect whose field they are in (playing in an NL park means the pitcher bats, playing in an AL park means the DH bats). Again this is a 2-3-2 best of 7 series.
2006-07-04 07:14:24 · answer #1 · answered by Joe J 4 · 5⤊ 0⤋
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2016-09-25 20:59:22 · answer #2 · answered by ? 4 · 0⤊ 0⤋
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2016-12-08 16:27:36 · answer #3 · answered by ? 4 · 0⤊ 0⤋
I believe the #1 overall record plays the wild card team, and the other 2 play each other. If it is still the 5 game initial format, the first 2 are at the higher seeds stadium, then it goes back for 2 more at the lower seeds and then a deciding game 5 at the higher seed.
The highest seed remaining in the NL/AL championship series then has the home field for 7 games.
The winner of the All Star game will determine who has home field in the World Series.
2006-07-04 07:06:53 · answer #4 · answered by JoeRevs300 2 · 1⤊ 2⤋
Not so much. It is whoever is in 1st place in each division is basically over .500. Then the contenders are in the wild card. They play each other in the same division and once a team is eliminated, then it keeps going until you have one team from the NL and one team from the AL. Those are the 2 teams in the World Series. Sorry if that was kind of confusing.
2006-07-04 07:07:00 · answer #5 · answered by houstonmom77064 3 · 0⤊ 3⤋
First off, there are no "brackets"---that is SO high school.
We are talking MLB here, and it's quite simple.
4 teams each league do the playoffs.
The first round is called "The Divisional Series"
The team with the best record plays the wild card team (unless the wild card team is in thier own divison, then they play the first place team with the lesser record.).
Then the remaining teams play each other.
The winner of "The Divisional Series" play for League Championship Series.
The winner of each league plays for The WORLD Series.
The winner of The WORLD Series are known as WORLD Champions.
Plain and simple.
2006-07-04 09:24:51 · answer #6 · answered by Anonymous · 1⤊ 6⤋
Three division winners plus one wild card (best record of the remaining teams) in each league. Then it's home field advantage by season record.
2006-07-04 07:06:33 · answer #7 · answered by GregW 4 · 0⤊ 3⤋
The same way it works for the NFL and the NBA: whoever wins moves up, whoever looses, drops off the chart into oblivia. LOL
2006-07-04 07:05:29 · answer #8 · answered by shehawke 5 · 0⤊ 8⤋