2006-07-04 04:11:28 · 8 answers · asked by xavier h 1 in Science & Mathematics ➔ Mathematics
Huh? You mean like all triangles have 180 degrees; quadrilaterals 360 degrees?
2006-07-04 04:15:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
For a polygon with n sides, the sum of the angles of the figure is 180*n-360.
2006-07-04 04:17:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
alpha = 360°/n for interior angles
beta = 180°(n - 2)/n for exterior angles
Once you know the exterior angles, just multiply them by how many sides you have. As for the interior angles, the add up to be 360. This is a assuming that all interior or exterior angles are the same.
2006-07-04 07:26:15 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
180(n-2)=sum of interior angles
to get the sum of exterior angles, take the result from above, divide it by the number of angles, subtract the number you get and re-multiply that number by the number of angles.
2006-07-04 05:13:49 · answer #4 · answered by Archangel 4 · 0⤊ 0⤋
(n - 2) x 180
Ex: for a triangle: (3 - 2 ) x 180
1 x 180
180
:)
2006-07-04 04:16:08 · answer #5 · answered by Christoou 1 · 0⤊ 0⤋
Which figure? Different figures mean different calculations!
2006-07-04 04:15:10 · answer #6 · answered by Sarah 3 · 0⤊ 0⤋
please write full question Which figure
2006-07-04 04:45:55 · answer #7 · answered by shahrukh 2 · 0⤊ 0⤋
depends on wat figure....
2006-07-04 04:15:14 · answer #8 · answered by ♥aggie luvr♥ 1 · 0⤊ 0⤋