A=[-2,4;0,3] and B= [-6,2;4,0]
2006-07-04 04:02:45 · 4 answers · asked by Nina E 1 in Science & Mathematics ➔ Mathematics
WELL THE ANSWER IS BA=[12 ,-18;-8,16]
OR BA=2{[6,-9;-4,9]}
2006-07-04 04:26:58 · answer #1 · answered by sss 1 · 0⤊ 0⤋
BA= a 2*2 matrix....
[-2*-6+4*4, -2*2+(-2*0); 0*(-6)+ 3*4, 0*2+3*0]
=[28, -4; 12, 0]
2006-07-04 11:26:38 · answer #2 · answered by raqandre 3 · 0⤊ 0⤋
BA =[-6*-2+2*0, -6*4+2*3;4*-2+0*0,4*4+0*3]
BA=[12,-24+6;-8,16]
BA =[12, -18;-8,16]
2006-07-04 11:39:58 · answer #3 · answered by munugala pallavi kishore 1 · 0⤊ 0⤋
I suppose you mean B x A...
You have to make couples using every B as first coordonate, and evety A as second coordonate...
(-6,-2),(-6,4),(-6,0),(-6,3)
(2, -2), (2,4), (2,0), (2,3)
(4,-2), (4,4), (4,0), (4,3)
(0,-2), (0,4), (0,0), (0,3)
2006-07-04 11:28:28 · answer #4 · answered by Christoou 1 · 0⤊ 0⤋