2006-07-04 03:06:25 · 9 answers · asked by lune_ellise 3 in Science & Mathematics ➔ Chemistry
In a graduated cylinder, measure an amount of water. Place the object in the water and note the water level change. The volume of water change is equal to the volume of the object if its density were the same as water (which of course it is not). Next you multiply by the proportional densities (density of water/density of object) the result is your volume of the object.
Example
You measure 50 ml of water. Next place a piece or red cedar in the cylinder. The water rises to 60 ml.
10 ml is the volume change this equals 10cc (1ml=1cc)
10 cc[(1g/cc)/(.38g/cc)] - (volume change times the proportional densities of water to red cedar)
answer the volume of the cedar is 3.8 cc
2006-07-04 04:05:20 · answer #1 · answered by Walt C 3 · 1⤊ 2⤋
1. Measure a known volume of liquid using a volumetric flask. Place the water in a callibrated vessel. The water placed in the volumetric flask should be enough to immerse the object whole while volume is being determined. Record this volume.
2. Add the object. Note the level of water caued by placing the object into the water.
3.Record the volume diplayed on the callibrated vessel.
4. Subtract the new volume from the old one. You'll get the volume of the object.
2006-07-04 03:26:42 · answer #2 · answered by javed 2 · 0⤊ 1⤋
It ought to have a density better than that of water or the fluid that's immersed in and it is going to in good shape into the field which you're immersing it in. a huge chuck of steel could be to massive for the flask which you're employing yet you are able to wreck it up in to products the piece can in good shape into the field.
2016-12-14 04:10:45 · answer #3 · answered by ? 4 · 0⤊ 0⤋
use a less dense liquid (like petrol), or perhaps attach something denser to it, first finding the volume of the heavier object by it's displacement, then refilling your vessel and finding the volume by difference?
2006-07-04 03:09:57 · answer #4 · answered by Stephan B 5 · 1⤊ 0⤋
You can depending on the shape of the object, measure it. lwh=volume.
2006-07-04 03:13:34 · answer #5 · answered by Darryl E 2 · 0⤊ 0⤋
Well you know its less than 1 so go with oil. It's less dense than water and will help refine you're answer
2006-07-04 06:23:35 · answer #6 · answered by shiara_blade 6 · 0⤊ 0⤋
Distillation!
Or layer separation using a graduated cylinder, as in, put them in the cylinder and let them separate, then measure.
Cheers.
2006-07-04 03:08:57 · answer #7 · answered by flammable 5 · 0⤊ 0⤋
what he said yea that the ticket!
2006-07-04 03:13:56 · answer #8 · answered by mike67333 6 · 0⤊ 0⤋
push it down
2006-07-04 03:09:43 · answer #9 · answered by Anonymous · 2⤊ 0⤋