English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I want to know if ders any shortcut to find sqaure roots of hard numbers like 14.567 or 1402.56 , etc/. using vedic maths.

2006-07-04 01:21:26 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

go to vedicmaths.org

2006-07-04 01:42:08 · answer #1 · answered by confused seeker... 2 · 1 0

sq. roots relate squares! so we will seem at "elementary to sq." numbers with base 50, 500, or a extra robust order. 40 8^2=23,04 40 9^2=24,01 50^2=25,00 base (initiate 2-digits are 25 and end 2-digits 00) 51^2=26,01 fifty two^2=27,04 498^2=248,004 499^2=249,001 500^2=250,000 (initiate-digits are 250 and end digits 000) 501^2=251,001 502^2=252,004 further any base 5000, 50000 or a extra robust order base may be mentally appropriate like "contraptions"-decrease than (or extra advantageous than) that are appropriate to base huge form to repair initiate 50% of answer-digits and end-digits are constantly (sq. of pronounced difference-"contraptions"). additionally see examples given decrease than! there is not any shrink to digits that could be concerning Vedic psychological computing! examples of extra digits numbers are (50000,00017)^2 = 2500000017,0000000289 (49999,99981)^2 = 2499999981,0000000361 approach is same as utilized to fewer digits base numbers 50, and 500 that have been discribed herinbefore! you are going to be able to study many extentions of pronounced procedures! on the tip of it you are going to be able to discover appropriate ability of computing squares (or sq. root of a sq.) which will purely relate reciprocal values of "few grasp-numbers" like... a million/9^2= 012345679 recurrs without end (a million is a million^2). 80/80 one=987654321 recurrs without end (80 is 9^2-a million^2). once you merge those 2 fee you get a merged huge form 012345679,987654321 it quite is (111,111,111)^2 you will discover 9 ifferrent squares (and sq. roots) in saifd merged fee like... initiate digit is 0,a million is end digit.(whilst merged a million^2) initiate digits 01,21 are end digits.(whilst merged 11^2) initiate digits 012,321 are end digits.(whilst merged 111^2) initiate digits 0123,4321 are end digits.(whilst merged 1111^2) etc... you are able to artwork out countless appropriate purposes! present day computers will help you to varify solutions! Your skill to word Vedic computing concepts additionally will improve your skill to apply computers effectively! Regards!

2016-12-10 04:23:01 · answer #2 · answered by Anonymous · 0 0

no my dear there is no short cut to find the sq root of such number except a calculator. the other way is to find out by long division method which is being taught in eight class in delhi

2006-07-08 20:02:11 · answer #3 · answered by xmax 1 · 0 0

fedest.com, questions and answers