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2006-07-03 05:22:12 · 11 answers · asked by cityturtleblue 2 in Education & Reference Other - Education

11 answers

y= 7 - 3x and y = 4x - 21
equate the two equations: 7-3x = 4x - 21
therefore 28=7x
x=28/7
x=4
therefore y=7 - 3(4)
y = -5

2006-07-03 05:28:06 · answer #1 · answered by Mezee 3 · 1 0

3x + y = 7 4x - y = 21 3x + y = 7 y = 7 - 3x 4x - y = 21 4x - (7 - 3x) = 21 4x - 7 + 3x = 21 4x + 3x = 21 + 7 7x = 28 x = 28/7 x = 4 4x - y = 21 4(4) - y = 21 -y = 21 - 16 -y = 5 y = 5/-a million y = -5 ? x = 4 , y = -5 (4,-5)

2016-11-05 21:13:03 · answer #2 · answered by valderrama 4 · 0 0

3x+y=7 4x-y=21

3x = 7 - y 4x = 21 + y

x = 7 - y / 3 x = 21 + y / 4

7 - y / 3 = 21 + y / 4

28 - 4y = 63 + 3y

28 - 63 = 3y + 4y

-35 = 7y
7y = -35

y = -35 / 7

y = -5

substitute y into 3x + y = 7

3x + (-5) = 7

3x - 5 = 7

3x = 7 + 5

3x = 12

x = 12 / 3

x = 4

[[ y = -5, x = 4 ]]

2006-07-03 05:38:25 · answer #3 · answered by K 4 · 0 0

This is solving for two variables using a system of simultaneous equations. In this case, by using the Addition Property, we can add the equations together, resulting 7x=28. Therefore, x=4. Using the Substitution Property, substitute x=4 into either equation to solve for y. y=-5.

2006-07-03 05:31:39 · answer #4 · answered by Vanessa 4 · 0 0

3x+y=7;4x-y=21 ;; solve for x by adding them together to get 7x=28: therefore x=4 then substitute in orig eq.:to get y= -5

2006-07-03 05:33:52 · answer #5 · answered by paulofhouston 6 · 0 0

add the two equations:

7x=28

x=4

put the value of x in any of the equations:

3*4 +y=7

y=-5

2006-07-03 05:31:08 · answer #6 · answered by bhaiyu 2 · 0 0

the answer is

x= 4
y= -5

2006-07-03 05:29:48 · answer #7 · answered by quikboy 7 · 0 0

3x+y=7.....x=(7-y)/3
4x-y=21....x=(21+y)/4

now,
(7-y)/3=(21+y)/4

now solve this...

2006-07-03 05:30:43 · answer #8 · answered by Anonymous · 0 0

You have to even the sides so...
yeah!

2006-07-03 05:26:11 · answer #9 · answered by miapia87 2 · 0 0

it's an algabra question!
~*Alyssa*~

2006-07-03 05:25:37 · answer #10 · answered by Anonymous · 0 0

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