Write the equation of the line that passes through point (–2, 16) with a slope of –4.?

Answer 1

y = mx + b where m is the slope and b is the y-intercept.

y = -4x + b
16 = (-4)(-2) + b
16 = 8 + b
b = 8

Therefore:
y = -4x + 8

Answer 2

You could use the point-slope equation since you know a point on the line and the slope of the line.
The form of the equation is (y - y1) = m(x - x1)
So, by substitution,
y - 16 = -4(x - (-2)) Then, just solve the equation to put in slope-intercept form.
y - 16 = -4x - 8
y = -4x +8

Answer 3

y = m * x + b
16 = -4 * -2 + b
16 = 8 + b
16 - 8 = 8 - 8 + b
8 = b
so...
y = -4 * x + 8