can you help me i'm in the 8th grd.what is the answer to 6x+2y=2 3x+5y=5?

Answer 1

2

Answer 2

2

Answer 3

Hi, this is called a system of equations. you can find the answer by either graphing both equations and finding the point where the two lines cross. (Just solve both equations for y first...then they are in y=mx+b form ... this is slope intercept form where m is the slope of the lline and b is the y intercept then graph.) Or you can sole one of the equations for either x or y and substitute into the other to solve....OR finally you could use eliminaton to solve. I would use elimination to solve since they are both in standard form (ax + by = c form) remember that in algebra you can do anything to any equation as long as you do the same thing to both sides and it will work out nicely:
6x + 2y = 2 ==---------------> 6x + 2y = 2
-2(3x + 5y = 5) would become -6x - 10y = -10

Now you can see that the x's will disappear....because 6x -6x =0
then we will have -8y = -8 left...(follow me?) divide both sides by -8 and y = 1. Now just plug y=1 into one of the ORIGINAL equations (6x + 2(1) = 2) and solve for the x and you got your answer! remember it will always be a point (x, y) where the two lines cross....in this case
6x + 2 = 2
-2 -2
so 6x = 0 and
x = 0
Then my point is (0,1) (when you graph the two lines this is where they will cross. When working problems like this it is important to remember that if either the x or the y disappears you have 2 lines that are either parallel (if the variables disappear and the resulting statement is false,,,there will be no solution of course because the lines will never cross ) or they are the same line (if the variables disappear and the resulting statement is true (also called an identity) because of course all solutions will be true because both lines are the same and they share all the same points!) HOPE THIS HELPS!!! tes

Answer 4

you can slove ths problem by using simultaneous equations.

6x + 2y = 2------call ths equation A
3x + 5y = 5------call ths equation B.

now, (equation A) - [2 X (equation B)]
this implies;

6x + 2y = 2
-6x - 10y = -10
--------------------------------
0 - 8y = -8
therefore y = 1

substituting y = 1 in equation B

3x + 5( 1 ) = 5
3x = 5 - 5
implies x =0

hence the ans to ur porb is x = 0 and y = 1

u can also do it using substitutions.

6x + 2y = 2
3x + 5y = 5 , from equation B we get x = (5 - 5y)/3

substitute this as the value of x in equaion A.

6{ (5 - 5y)/3 } +2y = 2

implies 2(5y - 5) + 2y = 2
10y - 10 + 2y = 2
therefore 12y = 12
y = 1

now x = ( 5 - 5y)/3
substituting y = 1 we get x = 0

i hope u can do similar kinda probs using either of these methods from now on. i personaly find the first method easier but i guess it's upto u.

Answer 5

First you have to find the value of either x or y in my chance I have choosen to find the value of y.

Hence (6x+2y =2)3
(3x+5y)=5)6

notice I have multiplied with the reverse number of x.

it will be 18x+6y =6 - i
18x+30y=30 - ii

Subract i from ii

You will get -24y = -24

therefore y = 1

put the value of y where in equation i

6x =2 = 2

6x = 2-2
x=0

Check against the two equation if the value is true

6(0) + 2 (1) = 2

3(0) + 5(1) = 5

So x = 0

y = 1

Answer 6

x = 0 y =1

Answer 7

Multiply to isolate each variable.

Find the GCF of 6x and 3x which is 12 so then multiply 6 times 2, and likewise 3 times 4 to get 12.

Perform rest of problem by adding both equation to one another. The x's should then cancel out leaving 0x+7y=7.

y=1

Do the same with the y variable or substitute back in to get x variable.

Answer 8

Lets see, heres how you solve this one-

1) The first thing we have to do is cancel out one of the variables-
so, lets cancel out the X variable since its easiest.

6x+2y=2 to 6x+2y=2
3x+5y=5 -6x-10y=-10

Did you see what I did? to cancel them out i multiplied the entire bottom line by -2.

2) Now we add up the variables like so

6x+2y=2
+ -6x-10y=-10
---------------------
0x-8y= -8

the X has been canceled out, so we're left with -8y= -8. When that's simplified we're left with y=1

3)Now that we know that y=1, we can go back to the original equations and put it in

6x+2(1)= 2 or 6x+2=2
3x+5(1)=5 3x+5=5

4) combining the equations again,
6x+2=2
+ 3x+5=5
-----------------
9x+7=7

5) Now we can solve for X

9x+7=7 to 9x=0, or x= 0


6) just to be sure we got it right, let's go back and substitute x and y in the original equation

6(0)+2(1)=2 or 2=2
3(0)=5(1)=5 5=5

so our final answer is, x=0 and y=1


There is another method of doing this where you solve one equation for a variable, then substitute it in the other.... but i always found that way to be a bit harder. I know some people like to do it this way so i'll go over it.

1)Lets solve for y in 6x+2y=2

2y=-6x+2
y=-3x+1

2) Now we put this equation into the other by substituting it for y

3x+5y=5 to 3x+5(-3x+1)=5

3) Now we solve for x. Don't forget to multiply the 5 to the entire parenthesis!

3x+5(-3x+1)=5 to 3x-15x+5=5 to -12x+5=5

-12x=0, or x= 0

4) Since x=0, we can go back to the first equation and sub it in

6x+2y=2 to 6(0)+2y=2 to 2y=2 or y=1


5) Remember to check your answers (we already did that)




Either way will work, but its just up to how you like to do it..

Hope that helps!

Answer 9

6x + 2y = 2
3x + 5y = 5

y = 1 - 3x <= From equation 1

3x + 5(1 - 3x) = 5
3x + 5 - 15x = 5
-12x = 0
x = 0

6x + 2y = 2
6(0) +2y = 2
y = 1

Therefore, x= 0, y=1

Answer 10

6x + 2y = 2 [Divide everything by 6]

x = 1/3 - 1/3y

[so go to the other equation, what we're doing is called solving using a system, and plus in the value we obtained for x]

so in 3x + 5y = 5 plug in

3(1/3 - 1/3y) + 5y = 5

we get

3 - 3y + 5y = 5

subtract 3 from both sides

-3y + 5y = 2

add 5y to -3y and we get

2y = 2

divide both sides by 2

y = 1

You're almost done!

Now plug in y to solve for x

6x + 2 = 2

subtract 2 from both sides

6x = 0

divide by 6 to get

x = 0

Now you've solved for both!