quick help?

Question

Chris invested $1200 in 2 small businesses. last year greeting card business made a 14% profit on her investment in the business. while the bicycle business showed a 6% loss. If chris net profit from the two businesses was $102, how much was her investment in the greeting card business?

he invested 2300 dollars not 1200

Answer 1

The investments on greeting cards is $1200 and profit $168
investment on bicycle business is $1100 and loss of $ 66 net profit being $168-$66=$102

Answer 2

I am going to go with 600 dollars for the simple fact that if she invested 1200 in to two small buisness the profit or the loss of either does not change how much she invested into them

Answer 3

There is enough here to work this problem it just also requires some estimation. Take a guess and plug a number in for x. You know it has to be more than half of the total. Then work the problem. total - x = y, then x * .14 munus y * .06, then look at this answer if it's too high adjust x down some, if it's too low adjust x up some. There may be more of a formula for this but I just don't remember back that far in my school history. But this works.

(14% * x) - (6% * y) = 102
x + y = 1200

x = 870

If working with 2300

x + y = 2300

x = 1200

Answer 4

According to the details given above, her investment in the Greeting Card Business was $870. Hope that helps you out...

Answer 5

Her investment in the greeting card business was $1200.00!

And yes there is plenty of information to answer this question so the above people are incorrect!

$1200.00 X 14% = $168.00

$1100.00 X - 6% = -$66.00

$168.00 - $66.00 = $102.00

Answer 6

not enough?