factorize x^2 - 25 and then some..?

Question

(a) Factorize x^2 - 25.

(b) use your answer in part (a) to find the factors of 119, other than 1 and 119.

show with steps if possible please (:

Answer 1

a) x^2-25 = (x+5)(x-5)

b) 119 + 25 = 144
so, if x = root 144 = 12 then
12^2 - 25 = 119
so the factors of 119 are
x+5 = 12+5=17
and
x-5 = 12-5=7

Answer 2

x^2 - 25 = ( x + 5) ( x - 5)

b) x^2 -25 = 119 (If I not interpreted wrongly)
X^2 = 144
X = 12.

The factors is 12 -5 = 7 & 12 + 5 = 17
Tje ans is 17, 7

Answer 3

(a):-

x^2 - 25 = (x+5) (x-5)
these are the factors asked in part (a)

(b):-

x^2 - 25 = 119
x^2 = 119 + 25 = 144
x=12
THUS THE FACTORS OF 119 ARE:-

(X + 5) = (12 + 5) = 17
AND
(X - 5) = (12 - 5) = 7

OR '17' AND '7 'ARE THE FACTORS OF 119 ASKED IN PART (b) OF THE QUESTION.

Answer 4

a) x^2-25 is factorised as (x+5)(x-5). We know a^2-b^2=(a+b)(a-b).
b) 119 can be expressed as 144-25 where 144 is 12^2.
119=144-25
=12^2-25 <<<< here x=12>>>>
=(12+5)(12-5)
=17*7.
So, the factors are 17 and 7.

Answer 5

you look at what provides as much as the midsection term...yet whilst greater is comparable to (hence) 25 So hence...its (x-5) (x-5) , its form of a trick, if it doesnt artwork..which it in some circumstances doesnt..you ought to use the quadratic formula. youll word that in case you amplify out what i wrote, youll get an identical element..that's the belief. must be trouble-free adequate to come across on the information superhighway. yet right here that's -b +- Sqrt (b^2 - 4ac) / 2 additionally dont forget approximately that x2 – 10x + 25 is comparable to 0. besides (x-5) (x-5) yet your answer is x= beneficial 5, you purely continuously opposite the sign. desire this permits

Answer 6

(a) Soln:
(x+5)(x-5)

(b) Soln:
x^2-25=119
x^2=144
x=12, therefore:
The factors are 7 and 17.

Answer 7

(a) (x + 5)(x - 5)

(b) a2 - b2 = 119
(a,b) = 10(sqrt 2) , 9

Factors of 119 = (10(sqrt 2) + 9) (10(sqrt 2) - 9)