Which is more accurate in calculating volume or a metal object ( a solid object in general):
a.) using water displacement
b.) by dimensions then using the formula V = (r^2) (3.14) (h)
Please provide your comment with some explanation to explain why your chosen method in calculating density is more accurate. Thanks.
2006-07-01 10:20:11 · 6 answers · asked by shungukusatsu 2 in Science & Mathematics ➔ Other - Science
It depends on the object. From the formula you provided, it seems you are thinking of a cylinder. If I wanted an accurate result for a metal cylinder I would either use water displacement, with a very accurate graduated cylinder to measure it or I would use the formula if I could measure the dimensions accurately, but I would use a few more decimal places of pi.
2006-07-01 10:25:36 · answer #1 · answered by mathsmart 4 · 0⤊ 0⤋
Depends on the geometry of the object. Your formula is for a cylinder. This would be most accurate for a cylinder that is perfectly smooth and perfectly round and perfectly straight. For anything else you'd need to either use the correct formula or water displacement.
Formulas are accurate when you're talking about objects that are perfect and have no irregularities. Water displacement has some error associated with it, due to water that clings to the object and the container and due to inaccuracies in the measurement of the volume, but it is much better at measuring objects that don't fit common formulas.
2006-07-01 17:29:28 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Your formula is for a cylinder and will not do for other shapes.
I think water displacement would be more accurate as weight can be measured with analytical balances very accurately, and also takes into account any irregularity in the object.
2006-07-01 20:49:05 · answer #3 · answered by Anonymous · 0⤊ 0⤋
it depends upon the calculating skill of the individual emperical numerical calculation can reveal facet of external appearance and texture i.e. grooves liquid displacement is quick and accurate for volume and if youhave the means you can do a radio spectroscopy if you are very careful with your intensity dynamic
2006-07-01 17:29:57 · answer #4 · answered by Book of Changes 3 · 0⤊ 0⤋
it depends on the shape. is it irregular?if so water displacement, if not use mathematical formulas for more regular shapes
2006-07-01 17:29:39 · answer #5 · answered by Anonymous · 0⤊ 0⤋
d
2006-07-01 17:23:58 · answer #6 · answered by Clayton_2_hotty 1 · 0⤊ 0⤋