2006-07-01 06:46:13 · 19 answers · asked by marcella i 1 in Science & Mathematics ➔ Mathematics
a(a+5)=14 -9 if a=1
2006-07-01 06:49:36 · answer #1 · answered by khansaab 5 · 0⤊ 0⤋
A=2
2006-07-01 07:02:03 · answer #2 · answered by Bryan 2 · 0⤊ 0⤋
2
2006-07-01 06:56:47 · answer #3 · answered by John G 1 · 0⤊ 0⤋
2
2006-07-01 06:50:34 · answer #4 · answered by BERNARD D 1 · 0⤊ 0⤋
a=2
2006-07-01 06:51:15 · answer #5 · answered by bellatara 2 · 0⤊ 0⤋
2(2+5)=14
2006-07-01 06:51:11 · answer #6 · answered by blondie 1 · 0⤊ 0⤋
a(a+5)=14 -?
2(2+5=14
2006-07-01 06:50:45 · answer #7 · answered by Anonymous · 0⤊ 0⤋
hmmm... let me rewrite this a bit..
a(a+5) = 14 - Y
if a = 0, then we have 0=14-Y and Y = 14
if a = -1 then we have -4 = 14 -Y and Y = 18
if a = 1 then we have 6 = 14 - Y and Y = 8
so you can see, there are many answers.. probably a curve of some kind.. so.. let's use a = X and rewrite the equation:
x(x+5) = 14-y
x^2 + 5x +y -14 = 0
or...
y = -x^2 -5x +14.. plot this
or.. with your original variable
? = -a^2-5a +14.. which is a parabolic curve
2006-07-08 02:33:23 · answer #8 · answered by ♥Tom♥ 6 · 0⤊ 0⤋
a=2; a= -7
2006-07-01 07:17:44 · answer #9 · answered by Mada S 2 · 0⤊ 0⤋
a(a + 5) = 14
a^2 + 5a = 14
a^2 + 5a - 14 = 0
This can be factored:
(a - 2)(a + 7) = 0
This is a true statement if either factor = 0, so set each factor to zero and solve for a.
a - 2 = 0
a = 2
a + 7 = 0
a = -7
You expect two solutions because the equation is a quadratic (degree 2).
2006-07-01 07:25:45 · answer #10 · answered by kindricko 7 · 0⤊ 0⤋