How do you solve (x^3-2x^2-4x+3)/(x-3)?

Answer 1

You can't solve it because it's not an equation, but you can reduce it.

(x^3 -2x^2 -4x +3) = (x-3)((x^2 +x -1)
This can be found using long division...I can't really show it here.

So the final answer would be (x^2 +x-1)

Answer 2

look x-3 is a factor of numerator (this u can confirm from the remainder theorm)so u simply divide the numerator by x-3 and get a quadratic equation which can be easily solved
by factorising

Answer 3

Long division of polynomials. I can't type it out here (requires too much spacing accuracy), but this site seems to explain it pretty well.

http://www.math.unt.edu/mathlab/longdiv.html


Edit to the two answers before me- If you read it guys, it's not actually an equation.

Answer 4

Separate the 'x' from the numbers on 2 sides of the equation, do the math, and you will have the answer.

Answer 5

Instead of long division, I suggest you try synthetic division. It's too long for me to explain here, so read about it here:
http://www.purplemath.com/modules/synthdiv.htm
It does the same thing as long division but with a lot less writing. Good luck!

Answer 6

Just do long division, except with polynomials here.
The answer is x^2 +x -1

Answer 7

(x^3 - 2x^2 - 4x + 3)/(x - 3)

3 | 1 -2 -4 | 3
| 3 3 | -3
-----------------------
| 1 1 -1 | 0

ANS : x^2 + x - 1

Answer 8

well , its so easy to doit, first of all perform along division finding the quadratic solution of dividing acubic function with a linear one.. then use x=[ -b(+ or -) sqrt (b^2-4ac)] / 2a where 'a' not = 0

Answer 9

Whenever I get stumped I go to this website. You just enter in the equation and it will show you each step on how to solve.

http://www.algebrahelp.com/calculators/equation/