2006-06-30 18:28:46 · 12 answers · asked by dancer4life421 1 in Health ➔ Other - Health
Perhaps you mean "titty hard-on", when someone's nipples get tumescent and hard.
Perhaps you mean "Tamils Health Organization", an organization in Sri Lanka.
Perhaps you mean "target hand-off" or "traditional hand-off", but that has nothing to do with health. Maybe you misspelled an initialism.
2006-06-30 18:42:53 · answer #1 · answered by me 5 · 0⤊ 0⤋
This Site Might Help You.
RE:
What does THO stand for?
2015-08-16 18:31:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋
no kidding. Learn something new every day. For a minute I thought she was getting all "And where fore aught THO Romeo" on us. I'm so glad it turned out porn-ish
2016-03-16 03:41:03 · answer #3 · answered by ? 4 · 0⤊ 0⤋
786.
you mean what i am fighting for? true answer ,unbaised , and heart felt , I cant imagine any living soul burning in the hell fire!
and if you really take me as your friend than it is more than painful to see a friend burning in a place that was not being created for him,and he could save himeself if he only wished for it!! its 100% heart felt feeling !!
2006-06-30 18:39:48 · answer #4 · answered by creative g 1 · 0⤊ 0⤋
That Hairy Oaf
Top Hat Oligarchy
Two hot owls
I can keep goin.......
2006-06-30 18:38:44 · answer #5 · answered by Whodaman 4 · 0⤊ 0⤋
Involving the female body-Titty hard on, other wise I have no idea
2006-06-30 18:33:31 · answer #6 · answered by shiloh 1 · 0⤊ 0⤋
Though
2006-06-30 18:32:03 · answer #7 · answered by Isabella's Mommy Expecting #2 6 · 0⤊ 0⤋
though, thou, thought, The heavy one, take handfuls only, two hearty onions, thousand, two hundred oxycontin, The holy one.............. It could be anything, I really don't know, tho.....
2006-06-30 18:36:16 · answer #8 · answered by matt H 2 · 0⤊ 0⤋
yes, Titty Hard On. Hope no one said this to you being disrespectful.
2006-06-30 18:34:57 · answer #9 · answered by Lets_see... 1 · 0⤊ 0⤋
Thor Industries .......maybe
2006-06-30 18:31:53 · answer #10 · answered by chastityelizabeth 5 · 0⤊ 0⤋