English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

4 answers

If it is specifically mentioned that it is a thin pipe (ratio of internal diameter to wall thickness greater than 20:1) then you can safely neglect the radial stress i.e. its value is zero. To find the longitudinal stress, you have to consider the end conditions and to find the tangential stress you have to use the equation for thin pressure vessel.

To be specific, according to your question, you can take the radial stress equal to 0.



To oil field trash:
You have stated the equation for tangential or circumferential stress not that for radial stress.


To Chris H:
Why do you mislead others? How dare you tell me I am wrong? In support of my statement I am furnishing the link to a note on Thin Cylinders below. Click on it and see how much ignorant you are about this topic. I have successfully completed a year-long project on Pressure Vessel Design. Before saying that someone is wrong, look carefully at his answer. I wrote "you can safely neglect the radial stress" not "the radial stress is always zero". In thin cylinders, only the membrane stresses are considered giving fairly accurate results.
The starting point in derivation of the equation
(S1)/(r1) + (S2)/(r2) = p/t
is to assume that the radial stress is zero and the hoop stress 'S1' and meridional stress 'S2' doesn't vary along the thickness.
Here 'R1' and 'R2' are radii of curvature in the circumferential and meridional planes, respectively, 'p' is the internal pressure and 't' is the wall thickness.
You may give a wrong answer to a question because you may be ignorant of its correct answer. That is alright. But when you challenge some answer be more careful in future, in Yahoo Answers as well as in your daily life.

2006-06-26 08:42:29 · answer #1 · answered by psbhowmick 6 · 2 0

This Site Might Help You.

RE:
calculations of radial stress in thin pipe under internal pressure?

2015-08-18 15:05:40 · answer #2 · answered by Annalee 1 · 0 0

Radial Stress

2016-11-12 22:29:41 · answer #3 · answered by ? 4 · 0 0

The radial stress in a thin pipe is equal to the internal pressure (not zero as stated above). It is usually ignored (or treated as zero) in combined stress calculations because it is at least an order of magnitude less than the hoop (tangential) stress and the longitudinal (axial) stress.

2006-06-26 14:50:34 · answer #4 · answered by Chris H 1 · 2 0

Multiply the internal diameter of the pipe in inches by the pressure in ponds per square inches. Divide this product by 2 times the thickness of the pipe in inches. the result will be the radial stress in the walls of the pipe.

2006-06-26 08:09:03 · answer #5 · answered by oil field trash 7 · 0 0

in fact ur question isn't clear... but if u mean arterial pressure measurement..i can answer u ..

measurement of arterial pressure is in brachial a. (at cubital fossa ) not radial a.
radial a. is used to measurement of heart rate ( no. of beats in one minute ) .

2006-06-26 08:28:10 · answer #6 · answered by mido_foxman 2 · 0 0

fedest.com, questions and answers