2006-06-23 08:02:25 · 28 answers · asked by Anonymous in Entertainment & Music ➔ Jokes & Riddles
In the dictionary.
2006-06-23 08:05:19 · answer #1 · answered by ratface29 2 · 0⤊ 0⤋
When it's Christmas of like 2005 and Thanksgiving of 2006.
2006-06-23 08:05:28 · answer #2 · answered by eissalc_13 2 · 0⤊ 0⤋
christmas was about 2000 years ago win it began but thanksgiving 4 about 400 years
2006-06-23 08:09:36 · answer #3 · answered by minime 3 · 0⤊ 0⤋
Christmas consistently falls on a diverse day, it rather is the twenty 5th of December each and each year. at diverse hand Thanksgiving is an afternoon that comes as at as quickly as as a year. in spite of the certainty that, as we communicate is properly known on diverse days in diverse international places. as an occasion, in usa, Thanksgiving is asserted a visit on the fourth Thursday of November. In Canada, Thanksgiving is asserted a visit on the 2nd Monday in October. So it rather relies upon each and each year as to on an identical time as Thanksgiving holiday occurs yet Christmas maintains to be the same each and each year in each and each u . s .. ineffective evening~Angel :)
2016-10-31 08:55:52 · answer #4 · answered by winstanley 4 · 0⤊ 0⤋
after thanksgiving and before christmas
2006-06-23 08:05:30 · answer #5 · answered by beerz24_7 3 · 0⤊ 0⤋
HA HA HA that's a good one i haven't heard that one before. i know it's proabably been around for like 100 years! (oh and the answer is: in the dictionary)
2006-07-05 15:56:55 · answer #6 · answered by soccerqueen155 2 · 0⤊ 0⤋
it is when christmas and thanksgiving run a race and chirstmas wins in it...
2006-07-05 23:38:46 · answer #7 · answered by Anonymous · 0⤊ 0⤋
dictionary alphabetical... unless its a japanese dictionary, thanksgiving will still be after because their books ar backwards.
2006-06-23 08:24:46 · answer #8 · answered by Anonymous · 0⤊ 0⤋
In the dictionary.
2006-07-04 13:50:38 · answer #9 · answered by Anonymous · 0⤊ 0⤋
In the dictionary!
2006-06-23 08:17:15 · answer #10 · answered by TaRdiS~dRivEr 2 · 0⤊ 0⤋